Ask question

Ask question

All categories

2 years ago

12

Which right triangle’s unknown leg measure is StartRoot 43 EndRoot units? Assume the given length are in the same unit of measur

e.
A right triangle has a side with length 5 and hypotenuse with length StartRoot 90 EndRoot.
A right triangle has a side with length StartRoot 44 EndRoot and hypotenuse with length 12.
A right triangle has a side with length StartRoot 19 EndRoot and hypotenuse with length StartRoot 60 EndRoot.
A right triangle has a side with length StartRoot 21 EndRoot and hypotenuse of 8.

2 answers:

Ksivusya [100]2 years ago

7 0

Answer:

your answer is d

Step-by-step explanation:

miv72 [106K]2 years ago

6 0

Answer:

D is the Answer

Step-by-step explanation:

You might be interested in

Here is a linear equation: y = 1/4x +5/4

docker41 [41]

Step-by-step explanation:

(1,1.5) is the solution but (12,4) is not the solution of given equation.

1.5=1/4×1+5/4(which is true)

4=1/4×12+5/4(which is false)

3 0

2 years ago

Read 2 more answers

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

Naddik [55]

Answer:

what a confusing question?

Step-by-step explanation:

im guessing 3 feet

8 0

2 years ago

Ally sliced 32 kg of watermelon for a party. She divided the watermelon slices equally between 8 large bowls.

igor_vitrenko [27]

Answer:

4000g

Step-by-step explanation:

32kg=32000g

32000/8 bowls=

4000g

3 0

3 years ago

I need help on 10 please explain

kumpel [21]

Lets approach this problem differently
15 gallons ....you drive ......330 miles lets divide both numbers by 15 to find out how much you can go with 1 gallon
1 gallon..... you drive.....330/15=22
you car goes 22 miles per 1 gallon
if you put 20 gallons
20*22=440 miles

6 0

3 years ago