The graph of y =f(x) is shown below. Find all values of x where f (x)=0 (check photo)

Write any equation in slope intercept form of the line that passes through the given point and it's parallel to the graph of the

Orlov [11]

Paralalell means that is has the same slope
y=mx+b
m=slope
y=-1x-2
slope=-1

the equation of a line that passes through the point (x1,y1) and has a slope of m is y-y1=m(x-x1)
given
(2,-2) and slope is -1
y-(-2)=-1(x-2)
y+2=-x+2
minus 2
y=-x
answer is y=-x

4 0

2 years ago

In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years. Assuming that life expectancy bet

Darya [45]

Answer:

49145 years

Step-by-step explanation:

In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years.

Assuming that life expectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and 2000,what will life expectancy be for women in 2100?

In 10 years, the expectancy increased by 85/45 = 17/9

between 2000 and 2100, it will increas by 10 time 10 years, so expected expectancy is $85*(\frac{85}{45})^{10} = 49145$ years

4 0

2 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

2 years ago

What is the distance between (-5,-6) and (-3,-8)

Sergio [31]

Answer:

x:-2

y:2

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The population of a town after t years is represented by the function f(t)=7,248(0.983)tf(t)=7,248(0.983)t.

lidiya [134]

Answer:

The population of the town is 0.983 times the population of the town in the previous year.

B is correct.

Step-by-step explanation:

We are given a function which represent population of a town after t years.

$f(t)=7248(0.983)^t$

It is an exponential function. Exponential function wither decease or increase it depends on factor.

$y=a\cdot b^x$

b is factor which decides factor of exponential function decrease or increase.

If b >1 then function increase

If 0<b<1 then function decrease.

If we see our problem $f(t)=7248(0.983)^t$

Here, b=0.983<1

Function would be decrease by factor of 0.983

Thus, The population of the town is 0.983 times the population of the town in the previous year.

7 0

2 years ago

Read 2 more answers