A situation could be when you have a y=axsquared+bx+c equation. You'd find the X, or vertex, by doing x=-b divided by 2•a. Then you'd plug in x and find y. Now you have a point you can plot. To find another, you can find the y-intercept by plughing in 0 for x and finding another y.
Answer:
The second plot.
Step-by-step explanation:
In the picture attached, the scatter plots are shown.
The second plot has minimum residuals and its residuals are randomly distributed. Residual is computed as follows:
residual = measured - predicted
It easy to see that residuals of the first option are greater than the second option.
Line of the second option is better than those from third and fourth options because residuals of the second option are randomly distributed, while in the third option, residuals are mostly negative; and in the fourth option, they are mostly positive.
6-2+4-8
= 4+4-8
= 8-8
= 0
I believe the answer is A. I’m sorry if this is incorrect.
A = pi times radius squared (radius is half the 16 inch diameter so 8 inches)
A = 3.14 x r^2
A = 3.14 x 8^2
A - 200.96 sq inches