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3 years ago

Which statement is NOT supported by the table

Mathematics

1 answer:

Greeley [361]3 years ago

7 0

I believe the answer is A. I’m sorry if this is incorrect.

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Am i right or am i wrong

frutty [35]

Answer:

you're right

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3 years ago

Consider 6x2 + 6x + 1. Which term immediately tells you that this expression is NOT a perfect square trinomial? Justify your ans

oksian1 [2.3K]

Answer:

Step-by-step explanation:

The 6x^2 because 6 is not a perfect square.

4 0

4 years ago

Read 2 more answers

Whats the area of the shaded region

barxatty [35]

Answer:

36 meter square

<h2>Please mark my answer as brainliest for further answers:)</h2>

4 0

3 years ago

Yall please help!!!!!! THANK YOUUU SO MUCHHH!!! Kinda lostttt

Georgia [21]

Answer:

Should be C

Step-by-step explanation:

Only the same power number can be use to add or subtract :)

But why is A, B and C same kinda stuff?

3 0

2 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago