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sasho [114]
3 years ago
15

How do you do this question?????

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0
It would 9 : 12 : 24

24 ÷ 8 = 3

4 • 3 = 12

3 • 3 = 9
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Other than 1, what are the perfect square factors for 792? From least to greatest.
Reika [66]

Answer:

Factors of 792: 1, 2, 3, 4, 6, 8, 9, 11, 12, 18, 22, 24, 33, 36, 44, 66, 72, 88, 99, 132, 198, 264, 396, 792. Factor pairs: 792 = 1 x 792, 2 x 396, 3 x 264, 4 x 198, 6 x 132, 8 x 99, 9 x 88, 11 x 72, 12 x 66, 18 x 44, 22 x 36 or 24 x 33.

Step-by-step explanation:

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4 years ago
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Pls help, solve and explain your answer.
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I don’t really know but I think one of them would be 150 adding 60 and 90
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Y = |x| translated one unit upward
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Answer:

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Step-by-step explanation:

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13.) Find the area of the shaded region if the side length of the square is 8 in.
sladkih [1.3K]

Answer:

<h3>Area of shaded region = 6.88 square inches</h3>

Step-by-step explanation:

Area of shaded region

  When we subtract the area of the circle from the area of square, we get the area of the 4 corners. When we divide that by 2, we get the area of 2 corners(shaded).
\sf \boxed{\text{Area of the shaded region =$\dfrac{Area \ of \ square - area \ of \ circle}{2}$}}

<h3>Square: </h3>

Area of square = side *side

                          = 8 * 8

                          = 64 square inches

<h3>Circle:</h3>

     diameter of the circle = side of the square

                                     d = 8 in

                                      r = 8/2 = 4 in

   \sf \text{Area of circle = \pi r^2}  Area of circle = πr²

                            = 3.14 * 4 * 4

                            = 50.24 square inches

\sf \text{Area of shade region = \dfrac{64 - 50.24 }{2}}

\sf \text{Area of the shade region = $\dfrac{64 - 50.24}{2}$}

                                       \sf = \dfrac{13.76}{2}\\\\= 6.88 \ square inches

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2 years ago
How to find the derivative of e^3㏑(x²)
vovikov84 [41]
f(x)=e^{3\ln x^2}\\\\f'(x)=e^{3\ln x^2}\cdot\dfrac{3}{x^2}\cdot2x=e^{3\ln x^2}\cdot\dfrac{6}{x}=\dfrac{6e^{3\ln x^2}}{x}\\\\\\but\ e^{3\ln x^2}=e^{\ln (x^2)^3}=e^{\ln x^6}=x^6\ where\ x\neq0\\\\therefore\ f'(x)=6x^5
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