Why cant you ask your teacher thats what they are for
Answer:
135 degrees
Step-by-step explanation:
step 1
Find the circumference of the circle
The circumference is equal to
we have
substitute
step 2
Remember that the circumference of the circle subtends a central angle of 360 degrees
so
using proportion
Find out the measurement of the central angle (in degrees) that intercepts an arc with a length of 9π/2 ft
The picture that you attached says it is unavailable
Answer:
we know that
the equation of the circle is of the form
(x-h)^2+(y-k)^2=r^2
where
(h,k) is the center of the circle
r is the radius of the circle
in this problem we have
(x+5)^2+(y-k)^2=r^2
so
the center is the point (-5,3)
the radius is 4 units
therefore
the answer is
The radius of the circle is equal to 4 units
Answer: False
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Explanation:
I'll use x in place of p.
The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.
Compare this to ax^2+bx+c = 0
We have
Plug those three values into the discriminant formula below
d = b^2 - 4ac
d = (-5)^2 - 4(10)(8)
d = 25 - 40*8
d = 25 - 320
d = -295
The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".
Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.
