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3 years ago

Round 14.603 round to the nearest hundredth

Mathematics

1 answer:

Studentka2010 [4]3 years ago

4 0

Answer:

I believe its 14.60

Step-by-step explanation:

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On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t

Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is $V_{hc}=-8\hat{i}-6\hat{k}$

The angle at which hailstones falling relative to the cyclist is $\theta = 36.86^\circ$

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of $2\hat{i}-6\hat{k}\text{ m/s}$ . If a cyclist travels through the hail at $10\hat{i} \text{ m/s}$ .

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is $V_h=2\hat{i}-6\hat{k}\text{ m/s}$

The velocity of the cyclist travels through the hail is $V_c=10\hat{i} \text{ m/s}$

The velocity of the hail relative to the cyclist is given by,

$V_{hc}=V_h-V_c$

Substitute the value in the formula,

$V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}$

$V_{hc}=-8\hat{i}-6\hat{k}$

So, The velocity of the hail relative to the cyclist is $V_{hc}=-8\hat{i}-6\hat{k}$

Now, The angle of hails falling relative to the cyclist is given by

$\theta = \tan^{-1}(\frac{-6}{-8})$

$\theta = \tan^{-1}(\frac{3}{4})$

$\theta = 36.86^\circ$

So, The angle at which hailstones falling relative to the cyclist is $\theta = 36.86^\circ$

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3 years ago

Which Equation represents the line passing through points a and C on the graph below

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Answer:

D!!

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Add the units between JK and KL together to get the answer for JL

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2 years ago

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Exclamation: of

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Answer:

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Step-by-step explanation:

25 minutes from 8:55 is 9:20

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2 years ago

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