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algol13
3 years ago
6

The probability a new purchase of a fiction novel is in the form of an e-book is 0.28. The probability a newly purchased fiction

novel is on the bestseller list is 0.4. Assume whether a new purchase of a fiction novel is in the form of an e-book is independent of whether the book is on the bestseller list. What is the probability a new purchase of a fiction novel is a book on the bestseller list given it is purchased in the form of an e-book
Mathematics
2 answers:
Nuetrik [128]3 years ago
7 0

Answer:

0.568

Step-by-step explanation:

ale4655 [162]3 years ago
6 0

Answer:

0.568

Step-by-step explanation:

P( e-book) = 0.28, P(On the bestseller list) = 0.4

Since event e-book and bestseller list are independent,

( Using formula, P( A OR B) = P(A) + P(B) - P( A AND B) )

P(e-book AND On the bestseller list) = P( e-book) * P(On the bestseller list)

P( e-book OR on the bestseller list) = P( e-book) + P(On the bestseller list)

- P( e-book) * P(On the bestseller list)

= 0.28 + 0.4 - 0.28 * 0.4

= 0.568

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During a road trip Tony , Tony drove one third the distance that Lana drove. Mark drives 15 more than Lana drove .The total dist
ale4655 [162]

Answer:

The distance drive by Lana = 201 miles

The distance drive by Mark = 216 miles

The distance drive by Tony = 67 miles  

Step-by-step explanation:

Given as :

The total distance cover by Lana , Tony , Mark = 484   miles

Let The distance drove by Lana = L   miles

The distance drove by Tony = T

The distance cover by Mark = M

So ,  L + T + M = 484 miles

Now, The distance of Tony = \frac{1}{3} of Lana distance

Or,   T = \frac{1}{3} × L

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Now.

   L + \frac{1}{3} × L + 15 + L = 484

Or, 2 L + \frac{L}{3} = 484 - 15

Or,  2 L + \frac{L}{3} = 469

Or,  \frac{7 L}{3} = 469

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∴     L =  \frac{1407}{7}

I.e   L = 201

The distance drive by Lana = 201 miles

The distance drive by Mark = 15 + L =15 + 201 = 216 miles

The distance drive by Tony =  \frac{1}{3} × 201 = 67 miles

Hence The distance drive by each person is

The distance drive by Lana = 201 miles

The distance drive by Mark = 216 miles

The distance drive by Tony = 67 miles    Answer

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3 years ago
Sean has 5.50 in dimes and quarters. he has 8 more quarters than dimes. how many quarters does he have
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Step 1: For the given data table on x^2

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Step-by-step explanation:

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Step-by-step explanation:

<u>Step 1:  Find the slope</u>

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