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Olenka [21]
3 years ago
7

Is there any potential negative effects immigration can have

Mathematics
2 answers:
uysha [10]3 years ago
8 0
Yes there could be negative effects by how hard it is...
Mama L [17]3 years ago
6 0
No there is not any effects
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Help!!!!!!!!!!!!!!! Please
Nonamiya [84]

Answer:

58.995 round to the nearest whole number is 59 miles per hour

Step-by-step explanation:

1 kilometer/hr = 0.62 miles per hour

Therefore 100 km/hr = 100 × 0.621

                                   = 62 miles per hour

95 km/hr = 95 × 0.621

              = 58.995 miles per hour

58.995 round to the nearest whole number is 59 miles per hour

   

7 0
3 years ago
On a scatter plot what does it mean when both variables are increasing
STatiana [176]
Both are getting bigger or increasing you need to rephrase the question 
4 0
3 years ago
Read 2 more answers
The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
3 years ago
A total of $20,000 is to be invested, some in bonds and some in certificates of deposit (CDs). If the amount invested in bonds i
Brilliant_brown [7]

Answer:

$8,500 in CDs; $11,500 in bonds

Step-by-step explanation:

Let c = amount invested in CDs.

Let b = amount invested in bonds.

"A total of $20,000 is to be invested, some in bonds and some in certificates of deposit (CDs)."

From the total investment, we get this equation.

c + b = 20000

"If the amount invested in bonds is to exceed that in CDs by $3000"

From the details of the amounts, we get this equation.

b = c + 3000

We have a system of equations in two unknowns.

c + b = 20000  Eq. 1

b = c + 3000  Eq. 2

Since Eq. 2 is already solved for b, we will use the substitution method to solve the system of equations.

Substitute b in Eq. 1 with c + 3000.

c + c + 3000 = 20000

2c + 3000 = 20000

2c = 17000

c = 8500

Now substitute c = 8500 in Eq. 2 and solve for b.

b = c + 3000

b = 8500 + 3000

b = 11500

Answer: $8,500 in CDs; $11,500 in bonds

6 0
3 years ago
3m² – 6m² - 7m +14<br>​
Reptile [31]
-3m^2 - 7m + 14. Hope it helps!
7 0
3 years ago
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