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marin [14]
3 years ago
9

Find another point on the line containing the points (-2,-3) and (3,-4)

Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

(8,-5)

Step-by-step explanation:

The slope of the line is -1/5, therefore one of the points is located at (8,-5)

Hope this helps!

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For a t distribution with 16 degrees of freedom, find the area, or probability, in each region.
cluponka [151]

Answer:

We are given the t distribution with 16 degrees of freedom.

We have to find the area a. to the right of 2.120

Answer: We can use excel to find the area to the right of 2.120. The excel function is:

=TDIST(2.120,16,1) = 0.025

Therefore, the area to the right of 2.120 is 0.025

b. to the left of 1.337.

Answer: We can use excel to find the area to the left of 1.337. The excel function is:

=1 - TDIST(1.337,16,1) = 0.900

Therefore, the area to the left of 1.337 is 0.900

4 0
3 years ago
In ΔKLM, the measure of ∠M=90°, the measure of ∠K=85°, and MK = 6.9 feet. Find the length of KL to the nearest tenth of a foot.
liq [111]
First take 180-90-85=5 for L angle then we can take tan(85)=ML/6.9, 6.9(tan(85))=ML. So ML=78.87ft. Now we can use Pythagorean theorem to find our KL so KL = sqrt((78.87)^2+(6.9)^2) and we get our answer KL=79.17ft. Hope it helps
3 0
3 years ago
Read 2 more answers
Larry invests $153.000 at 7% compounded quarterly, Moe invests 153,000$ at 7% compounded daily and Curly invests 153.000$ at 7%
grigory [225]
Hmmm I don’t really know
4 0
3 years ago
△ABC  is a right triangle with right angle C. Side AC is 6 units longer than side BC . If the hypotenuse has length 52–√ units,
Evgesh-ka [11]

Answer:

AC = 7.12 units

Step-by-step explanation:

A right triangle has two legs and a hypotenuse. The hypotenuse is opposite the right angle. As Angle C is the right angle, then the triangle can be constructed as shown in the picture attached. The sides of the triangle have a relationship known as the Pythagorean Theorem a² + b² = c². In the theorem, the legs of the triangle are a and b while the hypotenuse is c. Substitute a = x, b = x+6, and c = √52. Simplify and solve.

a² + b² = c²

x² + (x+6)² = √52²

x² + x² + 12x + 36 = 52

2x² + 12x - 16 = 0

You can use the quadratic formula to solve by substituting a = 2, b = 12, and c = -16.

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-12+/-\sqrt{12^2-4(2)(-16)} }{2(2)}=\frac{-12+/-\sqrt{144+128} }{4)}

\frac{-12+/-\sqrt{272} }{4}=\frac{-12+/-16.5 }{4} = 1.12, 7.13

Only 1.12 is a solution since 7.13 will not satisfy the Pythagorean theorem

Side AC is 6 units longer than side BC. This means x = BC and AC = x + 6.

AC = 1.12 + 6 = 7.12

6 0
4 years ago
That sounds like a good deal, but how about I give you 10 points for an answer.
Ilia_Sergeevich [38]
The answer is A - 1
Hope it helped
3 0
3 years ago
Read 2 more answers
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