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Gwar [14]
3 years ago
13

Find the median of the following data set.

Mathematics
2 answers:
JulsSmile [24]3 years ago
6 0

Answer:

Option B is correct.

Step-by-step explanation:

Given Data Set = 0.48 , 0.66 , 1.02 , 0.82 , 0.7 , 0.94

Number of observation in data set,N = 6

It is an even number.

So, Formula for Median = \frac{(\frac{N}{2})^{th}+(\frac{N}{2}+1)^{th}\:term}{2}

before using the formula we arrange data in increasing order or decreasing order.

Data set in increasing order = 0.48 , 0.66 , 0.7 , 0.82 , 0.94 , 1.02

Now,

Median =  \frac{(\frac{6}{2})^{th}+(\frac{6}{2}+1)^{th}\:term}{2}

             = \frac{3^{rd}+4^{th}\:term}{2}

             = \frac{0.7+0.82}{2}

             = \frac{1.52}{2}

             = 0.76

Therefore, Option B is correct.

Agata [3.3K]3 years ago
3 0

Answer: 0.76

Step-by-step explanation:

 

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mrs.bonnett's recipe for banana bread calls for three and one fourths cups of sugar. she wants to make 6.5 batches so that she h
Wewaii [24]

Answer:

21\frac{1}{8} Cups

Step-by-step explanation:

6.5(3\frac{1}{4} ) = 21\frac{1}{8}

6 0
3 years ago
Write out the equation: The difference of a number m and 30 is 10
inna [77]
M-30=10
It could also be 30-m=10
The answer for the first one would be 10+30=m
m=40
The answer for the second one would be 30-10=m
m=20

Hope this helps :)
4 0
4 years ago
Read 2 more answers
A certain type of automobile battery is known to last an average of 1110 days with a standard deviation of 50 days. If 100 of th
GalinKa [24]

Answer:

a. P(1104<X[bar]<1110) =  0.3849

b. P(X[bar]>1116) = 0.1151

c. P(X[bar]<940) = 0

Step-by-step explanation:

Hello!

Your study variable is X: "length of life of a battery" (days)

These batteries have a known lifetime average μ: 1110 days and a standard deviation δ:50 days.

To calculate the probabilities I'll apply the Central Limit Theorem, and since the sample is big enough (n>30), approximate the distribution of the sample mean to normal X[bar]≈N(μ;δ²/n) and use the standardization to the Z-distribution to calculate each probability.

a. The average is between 1104 and 1110

P(1104<X[bar]<1110) = P(X[bar]<1110) - P(X[bar]<1104)

= P(Z<(1110-1110)/(50/√100) - P(Z<(1104-1110)/(50/√100))

=P(Z<0) - P(Z<-1.2) = 0.5 - 0.1151 = 0.3849

b. The average is greater than 1116

P(X[bar]>1116) = 1 - P(X[bar]≤1116) = 1 - P(Z≤(1116-1110)/(50/√100))

=1 - P(Z≤1.2) = 1 - 0.8849 = 0.1151

Since the Z table accumulates from left, this means, the probability values it gives are P(Z), to calculate the values ​​above a certain number, you have to subtract from 1 (the highest possible cumulative probability value) all the cumulative probability that is below that number.

c. The average is less than 940.

P(X[bar]<940) = P(Z<(940-1110)/(50/√100)) = P(Z<-34) = 0

I hope you have a SUPER day!

5 0
3 years ago
What is the volume of a rectangular prism with length 6 mm, height 5 mm, and width 11 mm? V = lwh A. 330 mm B. 330 mm2 C. 330 mm
shepuryov [24]
The answer is 330mm3
3 0
4 years ago
A flagpole has a height of 10 yards. It will be supported by 3 cables, each of which is attached to the flagpole at a point 4 ya
Contact [7]
Pytagorean theorem

height10
attached at 10-4=6 yards from bottom
8 yards from base to away


a^2+b^2=c^2
a and b are side legnths and c=hypotonuse
so therfore we are given a and b and we must solve for c


so
6=height
8=base

6^2+8^2=c^2
36+64=c^2
100=c^2
square root
10=c

so therfor the legnth of each cable is 10 yards
3 cables so 3 times 10=30

30 yards needed

7 0
3 years ago
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