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ICE Princess25 [194]
3 years ago
6

Sydney has a bag of stuffed animals containing, 1 elephant, 4 bears, 3 cats, and 2 dogs. If she randomly selects 1 stuffed anima

l from the bag, places it on her bed and then selects another animal. What is the probability that she chooses a bear both times?
Mathematics
1 answer:
torisob [31]3 years ago
3 0

Answer:

2/15

Step-by-step explanation:

Step one:

given data

sample space

1 elephant,

4 bears,

3 cats, and

2 dogs.

sample size= 1+4+3+2= 10

Required:

By selecting without replacement, the probability that she chooses a bear both times

Step two:

the first event= Pr(bear)= 4/10= 2/5

the second event, the sample size is now 9 and the number of bears is now 3

Pr(bear)= 3/9= 1/3

Hence, the probability that she chooses a bear both times

= 2/5*1/3

=2/15

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Kamila [148]

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6+72=79 which is less than 90

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MATH<br><br> HELP<br><br> FIND THE EQUATION OF THE LINE
Dominik [7]

y=3/3x+-2

Step-by-step explanation:

it goes up 3 and over 3 so its 3/3 and it starts at -2

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2 years ago
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Item 1 A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. a. How many poss
egoroff_w [7]

Answer:

4 possible outcomes

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

P=\frac{x}{y}  

In this problem

<em>The probability of choose a blue card is </em>

x=7

y=7+4+6+8=25

substitute

P=\frac{7}{25}

<em>The probability of choose a green card is </em>

x=4

y=7+4+6+8=25

substitute

P=\frac{4}{25}

<em>The probability of choose a red card is </em>

x=6

y=7+4+6+8=25

substitute

P=\frac{6}{25}

<em>The probability of choose a yellow card is </em>

x=8

y=7+4+6+8=25

substitute

P=\frac{8}{25}

The sum of the probabilities of the 4 possible outcomes  is equal to

\frac{7}{25}+\frac{4}{25}+\frac{6}{25}+\frac{8}{25}=\frac{25}{25} ----> represent the 100%

4 0
3 years ago
Use simultaneous equations to solve the following. Three kilograms of jam and two kilograms of butter cost $29 and six kilograms
artcher [175]

Answer:

The cost of 1kg jam is $7 and the cost of 1kg butter is $4

Step-by-step explanation:

Let jam = x

butter = y

3x + 2y = 29 -----(1)

6x + 3y = 54 -----(2)

(1)×2 ->

6x + 4y = 58 -----(3)

(3)-(2) ->

y = 4

suby=4into(2)

6x + 3(4) = 54

6x = 42

x = 7

(Correct me if i am wrong)

6 0
3 years ago
Select the correct answer.
vovangra [49]

Answer:

B

Step-by-step explanation:

think of the ratios as equivalent fractions. 2 over 14 is NOT equal to 3 over 42.

6 0
3 years ago
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