Answer:
Solution given:
Volume of cone=⅓πr²h
Volume of cylinder=πr²h
1.
volume =πr²h=π*(10/2)²*6=<u>471.23mm³</u>
2.
Volume =πr²h=π*8*12.5=<u>314.16in³</u>
3.
volume =⅓πr²h=⅓*π*4²*3=<u>5</u><u>0</u><u>.</u><u>2</u><u>6</u><u>c</u><u>m</u><u>³</u>
4.
Volume =⅓πr²h=⅓*π*(8/2)²*12=<u>2</u><u>0</u><u>1</u><u>.</u><u>0</u><u>6</u><u>i</u><u>n</u><u>³</u>
Answer:
Step-by-step explanation:
Okay so you are gonna substitute x for 5 so the equations will look like y= (5)2+(5)2
So 10+10 = 20
So y=20
5,740,000( you have to make the number less than 10
5.740000 ( you put a decimal to make it less )
5.74e6 (you count how many times you skipped over to get at the decimal point , and that's your awnser .