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2 years ago

How to do this problem

Mathematics

1 answer:

borishaifa [10]2 years ago

8 0

5. since 2/3 cups goes into 1 tortilla , if she finds out how many 1/3 cups go into 8 cups, she would need to divide that amount

6, since it takes less than 1 cup for each tortilla, she should be able to fill more than 8

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The value of 7 in 67908 is blank times the value of 7 in 74702

Anastasy [175]

The value of 7 in 67098 is 7000 and the value of 7 in 74702 is 70000 or 700 so it is either 10 times or 1/10th of the the value.

4 0

3 years ago

Read 2 more answers

F(x) = 3x^3 - 2x^2 - 11x + 10; (x + 2) I need to factor and find the zeros.

Ratling [72]

Answer:

$\textsf{Factored function}: \quad f(x)=(x+2)(3x-5)(x-1)$

$\textsf{Zeros}: \quad x=-2, \quad x=\dfrac{5}{3},\quad x=1$

Step-by-step explanation:

Given function:

$f(x)=3x^3-2x^2-11x+10$

If (x + 2) is a factor then:

$\implies f(x)=(x+2)(ax^2+bx+c)$

Expand:

$\implies f(x)=ax^3+bx^2+cx+2ax^2+2bx+2c$

$\implies f(x)=ax^3+2ax^2+bx^2+2bx+cx+2c$

$\implies f(x)=ax^3+(2a+b)x^2+(2b+c)x+2c$

To find a, compare the coefficients of x³:

$\implies a=3$

To find b, substitute the found value of a into the coefficient for x² and compare:

$\implies 2a+b=-2$

$\implies 2(3)+b=-2$

$\implies b=-8$

To find c, compare the constants:

$\implies 2c=10$

$\implies c=5$

Therefore:

$\implies f(x)=(x+2)(3x^2-8x+5)$

Now factor (3x²-8x+5):

$\implies 3x^2-3x-5x+5$

$\implies 3x(x-1)-5(x-1)$

$\implies (3x-5)(x-1)$

Therefore the factored function is:

$\implies f(x)=(x+2)(3x-5)(x-1)$

Zero Product Property

$\boxed{\text{If \; $a \cdot b = 0$ \; then either \; $a = 0$ \;or \;$b = 0$ (or both)}.}$

To find the zeros, set each factor equal to zero and solve for x:

$\implies x+2=0 \implies x=-2$

$\implies 3x-5=0 \implies x=\dfrac{5}{3}$

$\implies x-1=0 \implies x=1$

Therefore, the zeros of the function are:

$x=-2, \quad x=\dfrac{5}{3},\quad x=1$

3 0

1 year ago

3. Two numbers are in the ratio 3:5. If their difference is 12, what are the numbers?

vladimir2022 [97]

I got 18 and 30 for my answer

8 0

3 years ago

(question 4 only plz)

Hatshy [7]

#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks

a) P(white) = $\frac{2}{6} = \frac{1}{3}$
P(red) = $\frac{1}{6}$
P(purple) = $\frac{3}{6} = \frac{1}{2}$

b)Not white block:
1 - $\frac{1}{3}$ OR $\frac{1}{2} + \frac{1}{6}$
$\frac{2}{3}$ $\frac{2}{3}$
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.

c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12

P(white)= $\frac{4}{12}$ which is still $\frac{1}{3}$

d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12

P(purple)= $\frac{5}{12}$
(im not quite sure if my explanation here helps you though)

e) 1 more of white and purple, 5 more of red
white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)

P(red)= $\frac{6}{12}$ = $\frac{1}{2}$

5 0

2 years ago

The picture shows a barn door:

spin [16.1K]

C

Opposite / hypotenuse
Sin 45 degrees= 7/x

8 0

2 years ago

Read 2 more answers