9x6<br><img src="https://tex.z-dn.net/?f=9%20%5Ctimes%206" id="TexFormula1" title="9 \times 6" alt="9 \times 6" align="absmiddle

Walnuts are 5 dollars a pound. Jack brought p pounds of walnuts and paid $25. Translate the following into a mathematical equati

Travka [436]

Answer:

7.95 per pound.

Step-by-step explanation:

8 0

3 years ago

the lenght of a room is twice its breadth and thrice its height if the cost of carpeting the floor at rs 80 per sq metre is rs 9

noname [10]

Answer:

Let's define the variables:

L = length of the room

B = breadth of the room

H = height of the room.

We know that:

L = 2*B

L = 3*H

Remember that the area of a rectangle of length L and breadth B is:

A = L*B

Then the area of the floor of the room is:

A = L*B

and L = 2*B, if we replace that, we get:

A = (2*B)*B

A = 2*B^2

Now, we know that the cost of carpeting the floor is $80 per m^2

And the total cost was $9000

Then the number of square meters in the floor (thus, the area of the floor) is:

A = ($9000)/($80) m^2

A = 112.5 m^2

With this, we can find the value of B.

A = 112.5 m^2 = 2*B^2

B = √( 112.5/2) m = 7.5 m

Then the length is:

L = 2*B = 2*7.5m = 15m

And the height is:

L = 3*H

H = L/3 = 15m/3 = 5m

Now that we know all the dimensions of the room, we need to find the area of the four walls, and the area of the ceiling (which is equal to the area of the floor 112.5 m^2)

Now, we will have two walls with an area of:

area = breadth*height = B*H = (7.5m)*(5m) = 37.5m^2

And two walls with an area of:

area = length*height = L*H = 75m^2

Then the total area of the four walls plus the ceiling is:

A' = 2*(37.5m^2) + 2*( 75m^2) + 112.5 m^2

A' = 337.5 m^2

And we know that for each m^2, the cost of plastering is $35

Then for 337.5 m^2, the cost will be 337.5 times $35

Cost = (337.5)*$35 = $11,812.50

4 0

2 years ago

4(y - 3) using distributive property

eduard

Answer:

4y - 12

Step-by-step explanation:

4(y - 3)

(4 x y) - (4 x 3)

8 0

2 years ago

HEEELLPPPP PLZ ASAP!!!!!!!!!!!!!!!!!

OLEGan [10]

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (4, 5) and (-3, -1). Substitute:

$m=\dfrac{-1-5}{-3-4}=\dfrac{-6}{-7}=\dfrac{6}{7}\\\\y-(-1)=\dfrac{6}{7}(x-(-3))\\\\\boxed{y+1=\dfrac{6}{7}(x+3)}$

3 0

3 years ago

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total

ehidna [41]

Answer:

The number of coach tickets bought was 9 and the number of first class tickets bought was 6

Step-by-step explanation:

Let'

x ---> the number of coach tickets bought

y ---> the number of first class tickets bought

we know that

The total of people is 15, so the total of tickets is 15

$x+y=15$ -----> equation A

She was able to purchase coach tickets for $180 and first class tickets for $1160. She used her total budget which was $8580

so

$180x+1,160y=8,580$ ----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (9,6)

see the attached figure

therefore

The number of coach tickets bought was 9 and the number of first class tickets bought was 6

5 0

2 years ago