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lorasvet [3.4K]
3 years ago
7

If using the method of completing the square to solve the quadratic equation

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

31.25

Step-by-step explanation:

The general form of a complete square would be (x + a)^2 + b

Given an equation of X^2 + 15X + 25 = 0,

the idea is to reduce it into the form if (X + C)^2

which can be expanded into X^2 + 2XC + C^2

In this case 15 will be our 2C So our c will be 7.5.

Substituting in these numbers,

We have X^2 + 15X + (7.5)^2 = 0

However our original equation has 25 for its C^2, thus

we need to add 31.25 in order to get (7.5)^2

<u>FYI</u>

The final completed form will be (X + 7.5)^2 - 31.25

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substitute the values in the formula above

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A=\frac{1}{3}

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\frac{1}{3}

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Subtract and simplify. Show work please!
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1) Final expression: +7y^2-6y-17

2) Final expression: 21x^3-46x^2+59x-30

Step-by-step explanation:

1)

The first expression is

(-2y^2-11y-7)-(-9y^2-5y+10)

First, we remove the 2nd bracket by changing the sign of all the terms inside:

-2y^2-11y-7-+9y^2+5y-10

Now we group the terms with same degree together:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)

Now we solve the expression in each brackets:

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So, this is the final expression.

2)

The second expression is

(7x-6)(3x^2-4x+5)

We apply the distributive property, so we rewrite the expression as follows:

(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)

Solving both brackets,

7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30

Now we group terms of same degree together:

21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30

And solving each bracket,

21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

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