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3 years ago

PLEASE SOMEONE HELP ME WITH THESE MATH QUESTIONS!!! VERY URGENT IF YOU ANSWER CORRECTLY, YOU'LL GET 10 POINTS!

Mathematics

1 answer:

Tasya [4]3 years ago

7 0

Answer:

Question 21: C.

Question 22: I.

Question 23: E.

Question 24: B.

Step-by-step explanation:

#21: The first statement is presented in the "Given" section.

#22: Since the reflexive property states that anything is equal to itself, BC ≅ BC.

#23: C being the midpoint of AD means that C is the same distance from both point A and point D. This then means that AC ≅ CD.

#24: AB ≅ DB due to the given, BC ≅ BC (since it's the same side), and we've proven that AC ≅ CD using a midpoint. We've proven <em>all three sides</em> on the two triangles to each other are congruent. This means that we've proven the triangles using SSS, which is B.

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Fred earned $22.50 in nine hours. how much did he earn after 4 hours? please show all your work

dusya [7]

I believe the answer is 10

22.50 divided by 9 to show how much for 1 hour. That is 2.5 so next 2.5 x 4 = 10

I don’t completely know if this is correct but I believe it is

6 0

3 years ago

Bill makes leather shoes. He charges $45 for a pair of women's shoes and $50 for a pair of men's shoes. He sells x pairs of wome

olga_2 [115]

$45x +$50y =$2,500
Since you want to know how many men's shoes he must sell to make $2500 , plug 0 in for x pairs of women's shoes.
$45(0) + $50y =$2,500
0 + $50y =$2,500
$50y = $2,500
$50y/50= $2,500/$50
y = 50

He must sell 50 pairs of men's shoes to still earn his weekly income of $2,500

Check

$45(0) + $50(50) = $2,500
$0 + $2500= $2,500
$2500 = $2500

3 0

4 years ago

Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.

julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

$f(x,y)=4x^2+6y^2$

Let g(x,y)= $x^2+y^2=1$

We have to find the extreme values of the given function

$\nabla f(x,y)$

$\nabla g(x,y)=$

Using Lagrange multipliers

$\nabla f(x,y)=\lambda \nabla g(x,y)$

$f_x=\lambda g_x$

$8x=\lambda 2x$

Possible value x=0 or $\lambda=4$

If x=0 then substitute the value in g(x,y)

Then, we get $y=\pm 1$

$f_y=\lambda g_y$

$12y=\lambda 2y$

If $\lambda=4$ and substitute in the equation

Then , we get possible value of y=0

When y=0 substitute in g(x,y) then we get

$x=\pm 1$

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

$f(0,1)=6$

$f(0,-1)=6$

$f(1,0)=4$

$f(-1,0)=4$

Therefore, the maximum value of f on the circle $x^2+y^2=1$ is $f(0,\pm1)=6$ and minimum value of $f(\pm1,0)=4$

7 0

3 years ago

Help pls ! <br> (Don’t type just to type)

Alex17521 [72]

Given equation

Combine like terms

Addition or subtraction property of like terms

Multiplication or division of property of equality

Addition or subtraction property of like terms

And then your answer or (given equation I’m assuming

7 0

3 years ago

A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the

Fynjy0 [20]

Answer:

a) 15.4% probability that a randomly selected person in this country is 65 or older

b) 0.023 = 2.3% probability that the person is 65 or older

Step-by-step explanation:

To solve b), i will use the Bayes Theorem.

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.7% of people in the county are under age 18

61.9% are ages 18–64

p% are 65 or older.

The sum of those is 100%. So

22.7 + 61.9 + p = 100

p = 100 - (22.7+61.9)

p = 15.4

15.4% probability that a randomly selected person in this country is 65 or older.

(b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

Event A: Uninsured

Event B: 65 or older.

15.4% probability that a randomly selected person in this country is 65 or older.

This means that $P(B) = 0.154$

1.4% of those 65 and older do not have health insurance.

This means that $P(A|B) = 0.014$

Probability of not having insurance.

22.7% are under 18. Of those, 5.4% do not have insurance.

61.9% are aged 18-64. Of those, 12.8% do not have insurance.

15.4% are 65 or over. Of those, 1.4% do not have health insurance. So

$P(A) = 0.227*0.054 + 0.619*0.128 + 0.154*0.014 = 0.093646$

Then

$P(B|A) = \frac{0.154*0.014}{0.093646} = 0.023$

0.023 = 2.3% probability that the person is 65 or older

5 0

3 years ago

PLEASE SOMEONE HELP ME WITH THESE MATH QUESTIONS!!! *VERY URGENT* *IF YOU ANSWER CORRECTLY, YOU'LL GET 10 POINTS!*

PLEASE SOMEONE HELP ME WITH THESE MATH QUESTIONS!!! VERY URGENT IF YOU ANSWER CORRECTLY, YOU'LL GET 10 POINTS!