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The maximum value of the objective function is 330
<h3>How to maximize the objective function?</h3>The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
#SPJ1
Answer:The object will hit the ground after 5 seconds
Step-by-step explanation:
Given height of tower =80 ft
h=-16+64t+80
When the object will hit the ground its height=0
0=-16+64t+80
Multiplying both sides by -1
16t²-64t-80=0
Dividing by 16 both sides
t²-4t-5=0
(t-5)(t+1)=0
t=5 or -1
So t=5 since time cannot be negative
The object will fall after 5 seconds