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taurus [48]
3 years ago
12

2. rate of change definition ​

Mathematics
2 answers:
Annette [7]3 years ago
6 0

Answer:Definition of rate of change. : a value that results from dividing the change in a function of a variable by the change in the variable velocity is the rate of change in distance with respect to time.

Step-by-step explanation:

Helen [10]3 years ago
4 0

Answer:

.

Step-by-step explanation:

A rate of change is a rate that describes how one quantity changes in relation to another quantity. If x is the independent variable and y is the dependent variable, then. rate of change=change in y change in x.

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The bank agrees to give you a loan of
dusya [7]
<h3>Answer: Monthly Payment = $12,083.34</h3>

========================================================

Explanation:

i = P*r*t ... simple interest formula

i = (1,500,000)*(0.03)*(15)

i = 675,000

The amount of interest you need to pay is $675,000

The total amount to pay back is 1,500,000+675,000 = 2,175,000 dollars.

Divide this over 180 months (since 15 years = 15*12 = 180 months) to get

(2,175,000)/180 = 12,083.3333333333

This rounds up to the nearest cent to get 12,083.34

I rounded up to make sure to clear the hurdle. Note how

180*(12,083.33) = 2,174,999.4

which is a bit short of the 2,175,000 mark we're after

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3 years ago
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shtirl [24]
The answer is 1. Yeah
5 0
3 years ago
Read 2 more answers
Really need help not good in geometry
Mandarinka [93]

Answer:18

Step-by-step explanation:It is the same shape just 3 times the size.

4 0
4 years ago
Agree or desagree ? short question ​
Dafna11 [192]

Answer:

Disagreee

Step-by-step explanation:

it has 6 sides so take 360/6 and you'll get 60, so it has to be rotated 60deg for it to be carried onto itself.

6 0
3 years ago
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\&#10;y-5=\pm \sqrt{x-2}\\&#10;y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
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