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3 years ago

13

What’s a complex conjugate in math

1 answer:

goldenfox [79]3 years ago

3 0

Answer:

Step-by-step explanation:

In mathematics, the complex conjugate of a complex number is the number with an equal real part and an imaginary part equal in magnitude but opposite in sign. For example, the complex conjugate of 3 + 4i is 3 − 4i. In polar form, the conjugate of is.

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The prime factors of a composite number must be less than a square root of the composite number. True or False?

Oksi-84 [34.3K]

Answer: It depends on what you're asking. If it can be equal, then yes. If it must be less, then no.

Step-by-step explanation:

Every composite number has a square root equal or less than its square root.

7 0

2 years ago

In the figure, triangle CAE is an enlargement of triangle CBD with scale factor of 4/3. The area of the smaller triangle is 9cm2

balandron [24]

Answer:

16 cm^2

Step-by-step explanation:

Given

$\triangle CAE$ -- Bigger Triangle

$\triangle CBD$ -- Smaller Triangle

$k = \frac{4}{3}$ --- Scale factor

Area of CBD = 9

Required

Determine the area of CAE

The area of triangle CBD is:

$A_1 = \frac{1}{2}bh$

$\frac{1}{2}bh = 9$

The area of CAE is:

$A_2 = \frac{1}{2}BH$

Where:

$B = \frac{4}{3}b$ and

$H = \frac{4}{3}h$

The above values is the dimension of the larger triangle (after dilation).

So, we have:

$A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h$

$A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h$

$A_2 = \frac{1}{2}*\frac{16}{9} *b* h$

Re-order

$A_2 = \frac{16}{9}*\frac{1}{2}* b* h$

$A_2 = \frac{16}{9}*\frac{1}{2}bh$

Recall that:

$\frac{1}{2}bh = 9$

$A_2 = \frac{16}{9}*9$

$A_2 = 16$

Hence, the area is 16 cm^2

3 0

2 years ago

Find the value of k by<br>quardractic equation two real and equal roots<br>5x - 2kx +20=0

kotegsom [21]

Answer:

k = +10 or -10

Step-by-step explanation:

It's given in the question that the roots of the eqn. are real and equal. So , the discriminant of the eqn. should be equal to 0.

$= > {b}^{2} - 4ac = 0$

$= > {( - 2k)}^{2} - 4 \times 5 \times 20 = 0$

$= > 4 {k}^{2} - 400 = 0$

$= > 4( {k}^{2} - 100) = 0$

$= > {k}^{2} - 100 = 0$

$= > k = \sqrt{100} = + 10 \: or \: - 10$

3 0

2 years ago

Read 2 more answers

PLSSS HELP IF YOU TURLY KNOW THISS

padilas [110]

Answer:

the answer is 5.31E37

Step-by-step explanation:

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2 years ago

Imagina que además de su trabajo en la bi biblioteca ,lizzie planea trabajar como voluntaria 3 horas por semana en un refugio de

Tamiku [17]

Answer:

(20 + 5w) + (10 + 3( w - 1 )) = 27 +8w

Step-by-step explanation:

¡espero que esto ayude!

3 0

2 years ago