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Rashid [163]
3 years ago
5

Estimate the product by rounding 2 x 6,254

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0
5 × 6,254= 31,300 is the awnser :)
You might be interested in
What is the area, in square centimeters, of the trapezoid below?<br> 8.5 cm<br> 7.5 cm<br> 15.7 cm
Contact [7]

Answer:

90.75 cm^2

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 ( b1+b2) *h

where b1 and b2 are the lengths of the bases and h is the height

A = 1/2(8.5+ 15.7) * 7.5

1/2 (24.2) 7.5

90.75 cm^2

6 0
2 years ago
A bus eats 4 people in a row and there are 12 rows how would fit on 2 buses?
BARSIC [14]

Answer:

4 \times 12 \times 2 = 96

96 people in total.

BTW its seats and I think you meant "how many"

6 0
3 years ago
How do you do this question?
erik [133]

Step-by-step explanation:

Use the first fundamental theorem of calculus.

∫₆¹⁰ f'(x) dx = f(10) − f(6) = 8 − 8 = 0

5 0
3 years ago
Helpppppppppppppppppp​
UNO [17]

Answer:

<em>2 solutions</em>

Step-by-step explanation:

Given the expression

2m/2m+3 - 2m/2m-3 = 1

Find the LCM of the expression at the left hand side:

2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1

open the bracket

4m²-6m-4m²-6m/(4m²-9) = 1

Cross multiply

4m²-6m-4m²-6m = 4m²  - 9

-12m = 4m²  - 9

4m²  - 9+12m = 0

4m² +12m-9 = 0

<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>

8 0
3 years ago
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
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