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Ne4ueva [31]
3 years ago
15

936 292 round to the nearest hundred thousand

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0

900,000 would be the nearest hundred thousand

sorry if it's wrong, but I did try

____ [38]3 years ago
7 0

Answer:

936,000

Step-by-step explanation:

You are going to round down because 292 is not 500 or higher and if you want to round up it has to be 500 or higher for this problem.

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Is x=5 a solution to the equation 19-x=14?
Musya8 [376]

Answer:

x = 5

Step-by-step explanation:

= 19 - x = 14

= 19 - x - 19 = 14 - 19

= -x = -5

= -x/-1 = -5/-1x

x = 5

Hope this Helps :D

7 0
2 years ago
How can one third x − 2 = one fourth x + 11 be set up as a system of equations?
timurjin [86]

Answer: (x-2) = (x+11)

------- -------

3 4

Step-by-step explanation:

First part is x-2 divided by on third. So the x-2 acts a the 1 so you put x-2 over 3. And you get:

(x-2)

--------

3

For the other side of the equation it is x +11 divide by 1/4. So the x+11 will act a the 1 in the fraction. And you will get:

(x+11)

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4 0
3 years ago
Read 2 more answers
Here is a screenshot of my question. Can somebody PLEASE help me understand this concept?
STatiana [176]

Same side interior angles need to equal 180 degrees when added together.

The same side interior angle, which would go with angle ACG would be CGE

8 0
3 years ago
Hi! Could you help me me out and solve these two problems? "eight less than the product of seven and xxx", and "the sum of six a
Ann [662]

Given:

The given statement are:

a. Eight less than the product of seven and x.

b. The sum of six and the product of three and d.

To find:

The expression for the given statements.

Solution:

a.

Product of 7 and x is 7×x = 7x.

Eight less than the product of seven and x is 7x - 8.

Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.

b.

Product of 3 and d is 3×d = 3d.

The sum of six and the product of three and d is 6+3d.

Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.

3 0
3 years ago
A pile driver falls freely from a height of 4.50 m above a pile. What is its velocity as it hits the pile? Remember to include y
faltersainse [42]

Answer:

9.4 m/s

Step-by-step explanation:

We are given that

Height of pile driver above a pile =h=4.5 m

Acceleration due to gravity=g=9.8m/s^2

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K.E=Potential energy

\frac{1}{2}mv^2=mgh

v^2=2gh

v=\sqrt{2gh}

Substitute the values

v=\sqrt{2\times 9.8\times 4.5}m/s

v=9.4 m/s

Hence, the velocity of pile driver as it hits the pile=9.4 m/s

6 0
4 years ago
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