Perform the requested operation or operations.
2 answers:
Answer:
Step-by-step explanation:
We have given two function f(x) and g(x)
We need to operate
Substituting the values in the above format we will get
after opening the parenthesis we will get
We will get after simplification the above expression
Addition of these two functions give us a quadratic expression means an expression with degree or highest exponent two.
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<span>First. <u>Finding the x-intercepts of </u>
</span><span>
Let be the change in water level. So to find the x-intercepts of this function we can use The Rational Zero Test that states:
To find the zeros of the polynomial:
We use the Trial-and-Error Method which states that a factor of the constant term:
can be a zero of a polynomial (the x-intercepts).
So let's use an example: Suppose you have the following polynomial:
where the constant term is
. The possible zeros are the factors of this term, that is:
.
Thus:
</span>
<span>
From the foregoing, we can affirm that
are zeros of the polynomial.
</span>Second. <u>Construction a rough graph of</u>
Given that this is a polynomial, then the function is continuous. To graph it we set the roots on the coordinate system. We take the interval:
![[-2,-1]](https://tex.z-dn.net/?f=%5B-2%2C-1%5D)
and compute
where 
is a real number between -2 and -1. If 
, the curve start rising, if not, the curve start falling. For instance:
Therefore the curve start falling and it goes up and down until
and from this point it rises without a bound as shown in the figure below
</span><span>
Let
To find the zeros of the polynomial:
We use the Trial-and-Error Method which states that a factor of the constant term:
can be a zero of a polynomial (the x-intercepts).
So let's use an example: Suppose you have the following polynomial:
where the constant term is
Thus:
</span>
From the foregoing, we can affirm that
</span>Second. <u>Construction a rough graph of</u>
Given that this is a polynomial, then the function is continuous. To graph it we set the roots on the coordinate system. We take the interval:
and compute
Therefore the curve start falling and it goes up and down until