Let's say if both work together, they can do it in "t" hrs
so, if Latoya can do it by herself in 14hrs, how much can she do in 1hr? well, she can do only 1/14 of the total
if Lisa can do it in 10hrs by herself, how much can she do in 1hr? well, 1/10 of the total
now, let's add their rate together, keeping in mind, their rate added, will be doing in 1hr only 1/t of the total work
thus
![\bf \cfrac{1}{14}+\cfrac{1}{10}=\cfrac{1}{t}\implies \cfrac{5+7}{70}=\cfrac{1}{t}\implies \cfrac{12}{70}=\cfrac{1}{t}\implies \cfrac{6}{35}=\cfrac{1}{t} \\\\\\ t=\cfrac{35\cdot 1}{6}\implies t=\cfrac{35}{6}\implies t=5\frac{5}{6}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B1%7D%7B14%7D%2B%5Ccfrac%7B1%7D%7B10%7D%3D%5Ccfrac%7B1%7D%7Bt%7D%5Cimplies%20%5Ccfrac%7B5%2B7%7D%7B70%7D%3D%5Ccfrac%7B1%7D%7Bt%7D%5Cimplies%20%5Ccfrac%7B12%7D%7B70%7D%3D%5Ccfrac%7B1%7D%7Bt%7D%5Cimplies%20%5Ccfrac%7B6%7D%7B35%7D%3D%5Ccfrac%7B1%7D%7Bt%7D%0A%5C%5C%5C%5C%5C%5C%0At%3D%5Ccfrac%7B35%5Ccdot%201%7D%7B6%7D%5Cimplies%20t%3D%5Ccfrac%7B35%7D%7B6%7D%5Cimplies%20t%3D5%5Cfrac%7B5%7D%7B6%7D)
so, they'd do it in 5hrs and 5/6 of an hour, which is just 50mins, so, 5hrs and 50mins
Answer:
h = 32.2 ft
Step-by-step explanation:
Since we have a right triangle, to get the value of h, we will have to use the appropriate trigonometric ratio
From the diagram given, h faces the angle and that makes it the opposite side
62.5 ft faces the right angle and that makes it the hypotenuse
The trigonometric ratio that connects the two is the sine
thus, we have it that;
sine 31 = h/62.5
h = 62.5 * sin 31
h = 32.2 ft
Answer:
All of these could do this.
Step-by-step explanation:
Normal distribution is a form of probability distribution that is symmetric about the mean, to depict data near the mean are more frequent in occurrence than data far from the mean. Normality of data can be measured by either power or the Shapiro-Wilk test.
Some ways of testing the normal distribution of data are by:
i. Histogram, which is a data visualization that shows the distribution of plotted sample data. The frequency of occurrence per value in the data set determines its distribution.
ii. Interpretation of the shape.
iii. Probability plot of the data, e.g Box Plot, QQ Plot etc. If the dots fall exactly on the black line, then a given sample of data are normal. If not, otherwise.
iv. Calculating interquartile range (IQR), which is a measure of variability. Sample of data are normally distributed when the interquartile range (IQR) is 1.34896.
Therefore, all the given methods could be used to determine if the data is normally distributed.
B. -5
F(-1)=2x-3
=2(-1)-3
=-2-3
=-5
They all can be a characteristics of a line except ITS WIDTH CAN BE MEASURED...