<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
Answer:
(x-12)^2+(y-2)^2=4
Step-by-step explanation:
Answer:
4W=25
providing the distances from the hanger wire to the weights are equal.
Step-by-step explanation:
Answer:
-√10,√11 , 3.30, 17/5
Step-by-step explanation:
-√10,√11 , 3.30, 17/5
17/5 is 3.4
the 10 is a negative so its the smallest
11 square root is a imiganery
