X > -10 + 5
bring the five to the other side of the equation and change the sign in front
x > -5
Most of the square numbers are even.so if we need to find root over we need an even number to convert it to perfect square.
See the example below
Some other triplets are
- (6,8,10)
- (5,12,13)
- (8,15,17)
Answer:
7z^3+6z^2-27z+22
Step-by-step explanation:
The given question is of subtraction:
So,
(7z^3+42z^2-15z+1)- (36z^2+12z-21)
=7z^3+42z^2-15z+1-36z^2-12z+21
Combining alike terms to simplify
=7z^3+42z^2-36z^2-15z-12z+1+21
=7z^3+6z^2-27z+22
So the answer in simplified form is:
7z^3+6z^2-27z+22 ..
X2-1 I think that's the answer because there's 1 less, 1 take away the x and squared!! hard to explain but that's how I thought about it
Answer:
3y^2 - (y + 2) (y - 2) = 0
<=> 3y^2 - (y^2 - 4) = 0
<=> 2y^2 + 4 =0
<=>y^2 + 2 = 0
=> Because y^2 is always equal or larger than 0, there is no real solution.
Hope this helps!
:)
