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Galina-37 [17]
2 years ago
6

Jennifer Kent receives 24 paychecks each year. Each check is for $863.50 before deductions. What is Jennifer's weekly salary?

Mathematics
1 answer:
Ymorist [56]2 years ago
7 0

There are 52 weeks in a year.


First multiply the amount of her check by the number of checks she gets:

863.50 x 24 = 20,724


Now divide that amount by 52 weeks:

20724 / 52 = $398.54 per week.



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Answer:

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Step-by-step explanation:

<u>How to Round:</u>

If the number following the number you're going to round up is 5 or above, (5, 6, 7, 8, or 9), then round up. (E.X. 2<u>9</u> rounded up is 30. Since 9 is above 5, you will round up.

On the other hand, if the number following the number you're going to round is 4 or below, (4, 3, 2, or 1), you don't round up, instead you keep it the same, and if they're are decimals, you turn the following numbers to 0s. (E.X. 32.4536 rounded to the nearest hundredth (32.45<u>3</u>6) is 32.45. Since 3 is less than 4, you're not going to round up. The number in the hundredth's place stays the same (5), and the following rest turn to 0s. Leaving you with 32.45

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2 years ago
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Papessa [141]

Answer:

Whats the question so that I can help?

Step-by-step explanation:

5 0
3 years ago
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Anuta_ua [19.1K]
Lets say you have 5 apples, but the you give away 3 of them.
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3 years ago
Ann increased the quantities of all the ingredients in a recipe by 60\%60%60, percent. She used 808080 grams (\text{g})(g)left p
kari74 [83]

Answer:

50 grams

Step-by-step explanation:

Let the amount of cheese required by the recipe be "x"

Ann increased 60% from original amount and then used up 80 grams. Thus:

<em>Original, increased by 60%, became 80</em>

<em />

This translated to algebraic equation would be:

x + 0.6x = 80

<u>Note:</u>  60% = 60/100 = 0.6

So we can solve the above equation for "x" and get our answer. Shown below:

x + 0.6x = 80\\1.6x=80\\x=\frac{80}{1.6}\\x=50

Hence,

the recipe required 50 grams of cheese

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2 years ago
What is a unit rate?
Ksivusya [100]

Answer:

<em>A unit rate is something over a unit of something else. </em>

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Hope this helps :)

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