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AnnZ [28]
3 years ago
14

Estimate the difference. Use benchmarks with decimal parts of 0, 0.25, 0.50, or 0.75.

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0
Your real exact answer would be 0.29 but a bench mark would be 0.25 so B
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a

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What is the answer to this equation? (picture attached)
SashulF [63]

Answer:

x = \frac{42}{5}

Step-by-step explanation:

Given

19 - \frac{5x+6}{4} = 7 ( subtract 19 from both sides )

- \frac{5x+6}{4} = - 12

Multiply both sides by - 4 to clear the fraction and the negative signs

5x + 6 = 48 ( subtract 6 from both sides )

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x = \frac{42}{5}

6 0
4 years ago
Carr Middle School is selling candy to raise money for their student activity fund. The school keeps one quarter of all candy sa
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Each candy should be $4.

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4 years ago
Elderly drivers. In January 2011, The Marist Poll published a report stating that 66% of adults nationally think licensed driver
katrin [286]

Answer:

(a) Hence, the margin of error reported by The Marist Poll was correct.

(b) Based on a 95% confidence interval the poll does not provide convincing evidence that more than 70% of the population think that licensed drivers should be required to retake their road test once they turn 65.

Step-by-step explanation:

We are given that the Marist Poll published a report stating that 66% of adults nationally think licensed drivers should be required to retake their road test once they reach 65 years of age.

It was also reported that interviews were conducted on 1,018 American adults, and that the margin of error was 3% using a 95% confidence level.

(a) <u>Margin of error formula is given by;</u>

             Margin of Error =  Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  

where, \alpha = level of significance = 1 - 0.95 = 0.05 or 5%

Standard of error =  \sqrt{\frac{\hat p(1-\hat p)}{n} }

Also, \hat p = sample proportion of adults nationally think licensed drivers should be required to retake their road test once they reach 65 years of age = 66%

n = sample of American adults = 1.018

The critical value of z for level of significance of 2.5% is 1.96.

So, <em>Margin of Error </em>=  Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  

                                =  1.96  \times \sqrt{\frac{0.66(1-0.66)}{1,018} } = 0.03 or 3%

Hence, the margin of error reported by The Marist Poll was correct.

(b) Now, the pivotal quantity for 95% confidence interval for the population proportion who think that licensed drivers should be required to retake their road test once they turn 65 is given by;

                   P.Q. =  \frac{\hat p-p}{ \sqrt{\frac{\hat p(1-\hat p)}{n} }}  ~ N(0,1)

So, <u>95% confidence interval for p</u> =  \hat p \pm \text{Margin of error}

                                                        =  0.66 \pm 0.03

                                                        =  [0.66 - 0.03 , 0.66 + 0.03]

                                                        =  [0.63 , 0.69]

Hence, based on a 95% confidence interval the poll does not provide convincing evidence that more than 70% of the population think that licensed drivers should be required to retake their road test once they turn 65 because the interval does not include the value of 70% or more.

7 0
4 years ago
3x - 7x =4<br> I need you to help me solve and work it out
djyliett [7]
3-7 is -4 so it becomes -4x=4 divide both sides by 4 to get -x=-1 a lot of teachers dont like that negative x so you can also divide by -1 again to make it x=1
hope it helps
4 0
3 years ago
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