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NARA [144]
3 years ago
7

This question worth 38 points to whoever answers it :)

Mathematics
2 answers:
Paraphin [41]3 years ago
4 0
Volumeprism=volumecube times number of cubes
vprism/vcube=number of cubes

vprism=12*5*4.25=255
vcube=side^3=(1/4)^3=1/64

vprism/vcube=255/(1/64)=255*64=16320 cubes

bearhunter [10]3 years ago
4 0
(12*5*4.25)(1/4)^3

255/(1/64)

255*64

16320

So 16320 cubes are needed to fill the prism.
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A.Find the total and area of the compound figures
goldfiish [28.3K]

Answer:

(a) The total area of compound figure is 284.52ft^2.

(b) The total perimeter of compound figure is 68.84 ft.

Step-by-step explanation:

Perimeter: The total distance covered by the figure.

Area: It is defined as the space occupied by the figure.

Given:

Length of rectangular figure = 19 ft

Breadth of rectangular figure = 12 ft

Radius of circle, r = \frac{12ft}{2} = 6 ft

Part (a):

Now calculating the total area of the compound figure.

\text{Total area}=\text{Area of rectangular figure}+\frac{1}{2}\times \text{Area of circle}\\\\\text{Total area}=\text{Length}\times \text{Breadth}+\frac{1}{2}\times \pi r^2

Now putting all the given values in this formula, we get:

\text{Total area}=(19ft\times 12ft)+\frac{1}{2}\times 3.14\times (6ft)^2\\\\\text{Total area}=284.52ft^2

Part (b):

Now calculating the total perimeter of the compound figure.

\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times \text{Circumference})\\\\\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)

Now putting all the given values in this formula, we get:

\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)\\\\\text{Total perimeter}=2\times 19ft+12ft+(\frac{1}{2}\times 2\times 3.14 \times 6ft)\\\\\text{Total perimeter}=68.84ft

8 0
3 years ago
Use the image below to answer the following parts.
12345 [234]

Answer:

Step-by-step explanation:

Part A

Since, the given angles are formed at a point are on a straight line, sum of these angles will be 180°.

Part B

(3x - 5)° + (4x + 2)° + (2x + 3)° = 180°

9x = 180

x = 20

Part C

m∠ADB = (3x -  5)°

             = (3×20 - 5)°

             = 55°

m∠DBK = (4x + 2)°

             = (4×20 + 2)°

             = 82°

m∠KBC = (2x + 3)°

             = (2×20 + 3)°

             = 43°

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3 years ago
Can the sides of a triangle have lengths 7, 7, and 1?
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Answer:

Yes

Step-by-step explanation:

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2 years ago
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