Let's set this ratio up as a fraction: (successful field goals)/(field goal attempts)
There were 439 successful field goals and 937 attempts: 439/937
The fraction cannot be reduced, so the ratio is 439/937.
C,
{(-1, -3),(0,-1),(1,1),(2,3),(3,5)}
Answer: 100+1.28(1/2)=100.64
Step-by-step explanation:
A random sample of size 16 is to be taken from a normal population having mean 100 and variance 4. ... The 90th percentile of the normal curve, according to the table I was provided, was equal to 1.28 standard units above the mean.
Answer:
50% chance
Step-by-step explanation:
(-6.5,0)
I hope this helps!