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yaroslaw [1]
3 years ago
14

What type of lone is x=-4

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0
What is the exact question here?
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Determine the difference: 3.2 × 1010 – 1.1 × 1011 Write your answer in scientific notation.
tekilochka [14]

Answer:

-7.8*10^{10}

Step-by-step explanation:

we have

3.2*10^{10} -1.1*10^{11}

we know that

3.2*10^{10}=0.32*10^{11}

substitute

0.32*10^{11} -1.1*10^{11}=-0.78*10^{11}=-7.8*10^{10}

4 0
3 years ago
Simplify fully: 12/5b² ÷ 3/10ab​
Ber [7]

Answer:

8a/b

.................

5 0
3 years ago
Read 2 more answers
3u - 3 = 15<br><br>give me a lecture so i can try to do it in the future please​
never [62]

Answer:

u=6

Step-by-step explanation:

One rule in algebra is what you do to one side, you do it to other side. So if you multiply a number in one side, multiply the same number in other side. Here in this question, you are trying to find the value of the variable u. Variable is called so because the value of it varies depending on different question. Here u is going to be a constant number which when multipled by 3 and then subtracted by 3 equals 15.

So first step is we try to get constants on one side. So we add 3 on both sides to get rid of 3 on left.

3u - 3 + 3= 15+3

3u= 18

Now we divide by 3 on both sides to get u by itself.

3u/3 = 18/3

u= 6

7 0
3 years ago
Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min
leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

                                \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2}.

First, we simplify the expression in the numerator of the fraction.

3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72

Now, we obtain

                         12(x^2-x-6) = 12(x+2)(x-3)

and the fraction is transformed into

                       \frac{3(2x-1)^2 - 75}{x+2} =  \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)

Therefore, the following limit is

       \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2}  12(x-3) = 12 \lim_{x \to -2} (x-3)

You can plug in -2 in the equation, hence

                        12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60

6 0
4 years ago
1.4=0.7p solve the equation
WINSTONCH [101]
You need to isolate p:
1.4 divided by 0.7 = 0.7p divided by 0.7 (this eliminates 0.7)
2 = p
4 0
3 years ago
Read 2 more answers
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