Answer:
B. y - 35 = 2(x - 10)
Step-by-step explanation:
The height of the plant, y, after x days could be modeled by the equation
<h3>y-y0=k(x-xo) (1)
,</h3><h3>
where y0 was the initial height at 'x0'th. day, and k is the constant of proportionality.</h3><h3>
From equation (1), k could be evaluated as follows:</h3><h3>
k=(y-y0)/(x-x0) </h3><h3>
From the problem statement, we may determine k by plugging in the given values, e.g. y0= 35, x0=10, y=55, x=20.</h3><h3>
Thus,</h3><h3>
k=(55-35)/(20-10)=2</h3><h3>
Therefore, the model equation becomes</h3><h3>
y-35=2(x-10)</h3><h3>
</h3>
Answer = 48.72
First find 16% of 42 which is just 16/100×42 which is 6.72 and then added 42
Answer:
Step-by-step explanation:
Problem One (left panel)
<em><u>Question A</u></em>
- The y intercept happens when x = 0
- That being said, the y intercept is 50. It was moving when the timing began.
<em><u>Question B</u></em>
The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2 miles / hour^2 (you have a slight acceleration.
<em><u>Question C</u></em>
- 60 = a + (n-1)d
- 60 = 50 + (n - 1)*2
- 10/2 = (n - 1)*2/2
- 5 = n - 1
- 6 = n
The way I have done it the domain is n from 1 to 6
Question 2 (Right Panel)
<em><u>Question A</u></em>
The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.
- f(0) = ax + b
- -3 = a*0) + b
- b = - 3
- So far what you have is
- f(x) = ax - 3
- f(-1) = a*(-1) - 3 but we know (f(-1)) = -6
- - 6 = a(-1) - 3 add 3 to both sides
- -6 +3 = a(-1) -3 + 3
- -3 = a*(-1) Divide by - 1
- a = 3
- f(x) = 3x - 3 Answer for f(x)
- The slope of f(x) = the coefficient in front of the x
- f(x) has a slope of 3
- g(x) has a slope of 4
<em><u>Part B</u></em>
- f(x) has a y intercept of - 3
- g(x) has a y intercept of -5
- f(x) has the greater y intercept.
- -3 > - 5
Answer:
The last answer.
Step-by-step explanation:
It looks to be the correct answer because for the one above you can't simplify 27 by 5.
