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Misha Larkins [42]
3 years ago
15

493,295. And the first nine is the number of rounding

Mathematics
2 answers:
evablogger [386]3 years ago
8 0

Answer:

490,000

Step-by-step explanation:

since 9 is the number we are rounding we look at the next number to the right and either we round up or down depending upon that number. since it is a 3 we round down but if it was a 5 or higher that number would be 500,000

VLD [36.1K]3 years ago
8 0

Answer: 490,000 or 493,300 depending on the nine you are rounding.

Step-by-step explanation:

if the number before the 9 is 5 or more, you round up, if its 4 or less you round down .

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(sec(π/3) + tan(-7π/4))/(1-cos(2 π/3))
Paha777 [63]

Answer:

3

Step-by-step explanation:

3+3_3=3

after that 3+2+6+7+7+8+8+9+9+9+9+9+0+0+8+6+5+4+ 5=?

u will do the answer and it will be done

6 0
3 years ago
Read 2 more answers
What is the solution set -4.9x +1.3 > 11.1
Irina18 [472]

Answer:

x < - 2

Step-by-step explanation:

given - 4.9x + 1.3 > 11.1 ( subtract 1.3 from both sides )

- 4.9x > 9.8 ( divide both sides by - 4.9 )

Remembering to reverse the direction of the inequality symbol as a result of dividing by a negative quantity.

x < - 2 ← inequality reversed

solution set : x ∈ ( - ∞, - 2 )


8 0
3 years ago
ILL GIVE U STUFFFFF PLZZZZZZZZZZZ ANSWER ITTTTTTTTT
belka [17]

Answer:

Slope: -\frac{3}{4}

Y-intercept: 399

Slope-intercept form: y=-\frac{3}{4}x+399

Step-by-step explanation:

1. The equation in Standard form is given in the problem:

3y+4y=1596

2. Then, to write the equation of the line in slope-intercept form  y=mx+b, where <em>m</em> is the slope and <em>b</em> is the y-intercept, you must solve for <em>y</em> as you can see below:

4y=-3x+1596\\y=\frac{-3x+1596}{4}\\y=-\frac{3}{4}x+399

3. Therefore, the slope and the y-intercept are:

m=-\frac{3}{4}\\b=399

5 0
3 years ago
(3x+2)∧2=9 how do i solve this in the square root property
Irina18 [472]
(3x+2)^2=9 \\\\9x^2+12x+4-9=0\\\\9x^2+12x-5=0\\\\a=9,\ \ b=12, \ \ c=-5

x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-12-\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12-\sqrt{144+180}}{18}=\\\\=\frac{-12-\sqrt{324}}{18}=\frac{-12-18}{18}=\frac{-30}{18}=-\frac{5}{3}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-12+\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12+18}{18}=\frac{6}{18}=\frac{1}{3} \\\\Answer: \ x=-\frac{5}{3}\ \ and \ \ x=\frac{1}{3}
 

6 0
3 years ago
Solve using substitution.<br><br> y = –9x − 1<br><br> y = –4x − 6<br><br> ( __ , __ )
Alenkasestr [34]

Answer:

x=-y-1/9

y=9x-1

x=-y/4-3/2

y=-4x-6

4 0
3 years ago
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