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2 years ago

Please please help me!!

Mathematics

1 answer:

Alona [7]2 years ago

4 0

Answer:

g(x) = f(x+1) + 1

Step-by-step explanation:

Since the graph is only moved you don't have to worry about the slope.

To move the graph to the left you add to the x and in this case, it only moved 1 over.

to move the graph up you add to the whole function and in this case, it only moved up 1.

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-8x-27=-7\left(1+2x\right)+2x

Darina [25.2K]

Answer:

$x=5$

Step-by-step explanation:

$-8x-27=-7\left(1+2x\right)+2x$

Expand:

$-8x-27=-7\times 1-7\times 2x+2x$

$-8x-27=-7-12x$

Add 27 to both sides:

$-8x-27+27=-7-12x+27$

$-8x=-12x+20$

Add 12x to both sides:

$-8x+12x=-12x+20+12x$

$4x=20$

Divide both sides by 4:

$\frac{4x}{4}=\frac{20}{4}$

$x=5$

5 0

2 years ago

Pleaseeeeeee help mee

BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

Step(i):-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

Step(ii):-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

verification :-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago

What is the least common denominator for 1/8, 1/9 and 1/12

Alona [7]

The least common denominator for 1/8, 1/9 and 1/12 is 24

5 0

2 years ago

Which expression is equivalent to 5a+20? A: 5(5a+4). B: 5(a+4). C: 5(a+20). D: 5(a+1)

guajiro [1.7K]

Answer:

5(a+4)

Step-by-step explanation:

expression is equivalent to 5a+20

To get the equivalent expression we need to factor the given expression

5a+ 20

5a can be written as 5 * a

20 can be written as 5*2*2

WE can see that common factor is 5 for both 5a and 20

So GCF is 5

Now we factor out GCF 5

WE put 5 outside and write all the left of factors inside the parenthesis

5a +20

5 (a+2*2)

5(a+4)

4 0

3 years ago

How do you factor m^2=2m? <img src="https://tex.z-dn.net/?f=m%20%5E%7B2%7D%20%20%3D%202m" id="TexFormula1" title="m ^{2} = 2

Sonbull [250]

First move all terms to one side:

$m^2=2m\implies m^2-2m=0$

Then all terms on the left side share a common factor of $m$ :

$m(m-2)=0$

The zero product product property says that if $ab=0$ , then $a=0$ or $b=0$ . So either $m=0$ or $m-2=0\implies m=2$ .

5 0

3 years ago