<span>To do that, you need to set it all to zero and factor:
x^2+8x+15 = 0
(x+5)(x+3) = 0
then put both those in parentheses chunks in their own equations
x + 5 = 0
x + 3 = 0
and then simplify
x = -5
x = -3
So the two points where the parabola crosses the x-axis are -5 and -3.</span>
Answer: 103
Step-by-step explanation:
Answer:
Step-by-step explanation:
If the area of trapezoid is 100 cm²what is the perimeter of the trapezoid?
Area of a trapezoid = 100cm
= 1/2(a + b) × h = 100cm²
Perimeter of a trapezoid = a + b + h
11011₂ = 2⁴ + 2³ + 2¹ + 2⁰ = 27
15 + <em>x</em>₂ = 27
<em>x</em>₂ = 12 = 8 + 4 = 2³ + 2² = 1100₂
