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3 years ago

What are the solutions to the equation |2x-3|+4=17

Mathematics

2 answers:

natta225 [31]3 years ago

8 0

First, let's subtract both sides by 4:

|2x - 3| = 13

We can get two different equations from this:

2x - 3 = 13

and

2x - 3 = -13

So:

2x = 16

2x = -10

x = 8, x = -5

The solution set is {8, -5}

zubka84 [21]3 years ago

3 0

$|2x-3|=\left\{\begin{array}{ccc}2x-3&for&2x-3\geq0\to x\geq1.5\\-(2x-3)&for&2x-3 < 0\to x$

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2 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is: