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4 years ago

Prove that sin alpha × sin(90- alpha) - cos(90-alpha) × cos alpha

Mathematics

1 answer:

satela [25.4K]4 years ago

8 0

Answer:

It is equal to 0.

Step-by-step explanation:

I can simplify it as follows:

sinα sin(90 - α) - cos(90 - α)(cosα)

Now sin(90 -α) = cosα and cos(90 - α) = sinα) ( for α < 90)

So the expression becomes:

sinαcosα - sinαcosα

= 0 .

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Please refer to the photo attached. (Apologies for the legitimately terrible drawing)

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2 years ago

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4 years ago

Prove that sin alpha × sin(90- alpha) - cos(90-alpha) × cos alpha​

Prove that sin alpha × sin(90- alpha) - cos(90-alpha) × cos alpha