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Mariulka [41]
4 years ago
5

Prove that sin alpha × sin(90- alpha) - cos(90-alpha) × cos alpha​

Mathematics
1 answer:
satela [25.4K]4 years ago
8 0

Answer:

It is equal to 0.

Step-by-step explanation:

I can simplify it as follows:

sinα sin(90 - α) - cos(90 - α)(cosα)

Now  sin(90 -α) = cosα and cos(90 - α) = sinα)    ( for α < 90)

So the expression becomes:

sinαcosα - sinαcosα

= 0 .

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