Answer:
The dilation is an enlargement
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is equal and this ratio is called the scale factor
In this problem Triangles A'B'C' and ABC are similar by AA Similarity Postulate
Let
z------> the scale factor
so
substitute the values
The scale factor is greater than 1
therefore
The dilation is an enlargement
It would be D. because the volume of a sphere is 4/2 x pi x radius^3.
Answer:
Question unclear
Step-by-step explanation:Your probally asking what times 8 gives us 80. If you are than 10!
Answer:
√3
√5
22/7.
16/4
Step-by-step explanation:
22/7 = 3.14
√3 = 1,73
16/4 = 4
√5 = 2.23
the least would have the smallest value. the greatest would have the largest value
as you can see above... notice the middle term, in a perfect square trinomial, the middle term is, 2 times the guy on the left, without the exponent, and times the guy on the right
so.. .what we have here ... let's see yours is
so.. we have a missing guy there, the guy on the right hmm what the dickens would that be anyway?
well... let us use the middle guy
aha ... there's our guy on the right.... so now we know is 1/5
now... let us call or very good friend Mr Zero, 0
if we "add" whatever, we also have to "subtract" whatever, since all we're really doing is, borrowing from 0
thus
![\bf x^2-\cfrac{2}{5}x\implies x^2-\cfrac{2}{5}x\quad +\left( \cfrac{1}{5} \right)^2\quad -\left( \cfrac{1}{5} \right)^2 \\\\\\ \left[ x^2-\cfrac{2}{5}x +\left( \cfrac{1}{5} \right)^2 \right]-\left( \cfrac{1}{5} \right)^2\implies \left( x-\cfrac{1}{5} \right)^2 - \cfrac{1^2}{5^2} \\\\\\ \left( x-\cfrac{1}{5} \right)^2 -\cfrac{1}{25}](https://tex.z-dn.net/?f=%5Cbf%20x%5E2-%5Ccfrac%7B2%7D%7B5%7Dx%5Cimplies%20x%5E2-%5Ccfrac%7B2%7D%7B5%7Dx%5Cquad%20%2B%5Cleft%28%20%5Ccfrac%7B1%7D%7B5%7D%20%5Cright%29%5E2%5Cquad%20-%5Cleft%28%20%5Ccfrac%7B1%7D%7B5%7D%20%5Cright%29%5E2%0A%5C%5C%5C%5C%5C%5C%0A%5Cleft%5B%20x%5E2-%5Ccfrac%7B2%7D%7B5%7Dx%20%2B%5Cleft%28%20%5Ccfrac%7B1%7D%7B5%7D%20%5Cright%29%5E2%20%5Cright%5D-%5Cleft%28%20%5Ccfrac%7B1%7D%7B5%7D%20%5Cright%29%5E2%5Cimplies%20%5Cleft%28%20x-%5Ccfrac%7B1%7D%7B5%7D%20%5Cright%29%5E2%20-%20%5Ccfrac%7B1%5E2%7D%7B5%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cleft%28%20x-%5Ccfrac%7B1%7D%7B5%7D%20%5Cright%29%5E2%20-%5Ccfrac%7B1%7D%7B25%7D)
