Answer:
He used about 15 gallons
Step-by-step explanation: if he drove 617.3 miles and he gets 41 miles per gallon, then we can use the formula 41x=617.3 to solve this formula, we would divide 617.3 by 41 to isolate x. 617.3 divided by 41 is equal to 15 and therefore x = 15
8.55*18-8.45*18
(8.55)(18)-(8.45)(18)
=153.9 - (8.45)(18)
=153.9 - 152.1
=1.8
hope this was helpful
0.10x+0.25y=11.40
remove the x and bring it to the other side using opposite operation getting:
0.10+0.25y=11.40x
remove the 11.40 from the right side to the left.
(0.10+0.25y)/11.40=x
I hope that helped. It's kind of confusing since there's no value for y.
Answer:
5+37=4-3x
We move all terms to the left:
5+37-(4-3x)=0
We add all the numbers together, and all the variables
-(-3x+4)+5+37=0
We add all the numbers together, and all the variables
(hope that helps you out)
-(-3x+4)+42=0
We get rid of parentheses
3x-4+42=0
We add all the numbers together, and all the variables
3x+38=0
We move all terms containing x to the left, all other terms to the right
3x=-38
x=-38/3
x=-12+2/3
(just in case you didn’t want it in the comments)
Switch the x and y values to find the inverse.
<span>y=<span>x−3x+2</span></span>
The inverse is given by
<span>x=<span>y−3y+2</span></span>
Solve for y now:
<span>x(y+2)=y−3</span>
xy+2x=y−3
2x+3=y−xy
<span>2x+3=y(1−x)</span>
<span><span>2x+31−x</span>=y</span>
The inverse, <span><span>f−1</span>(x)</span>, is given by <span><span><span>f−1</span>(x)</span>=<span>2x+31−x</span></span>.
The function can be graphed using knowledge of asymptotes, invariant points, and intercepts. Prepare a table of values for <span>f(x)</span>. Recall that <span><span>f−1</span>(x)</span> is simply a transformation of(x) over the line y=x, so <span><span>f−1</span>(x)</span> has a table of values where X and y are inverted relative to <span>f(x)</span>.
For example, if the point (2,3) belongs on the graph of <span>f(x)</span>, the point (3,2) belongs on <span><span>f−1</span>(x)</span>.
Replace <span><span>F<span>(X)</span></span><span>FX</span></span> with <span>yy</span>.<span><span>y=<span><span><span>X3</span>+<span>2X</span></span><span><span>−3</span>X</span></span></span><span>y=<span><span><span>X3</span>+<span>2X</span></span><span><span>-3</span>X</span></span></span></span>Interchange the variables.<span><span>X=<span><span><span>y3</span>+<span>2y</span></span><span><span>−3</span>y</span></span></span><span>X=<span><span><span>y3</span>+<span>2y</span></span><span><span>-3</span>y</span></span></span></span>
