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Scilla [17]
2 years ago
11

A cylindrical water tank has a diameter of 4 m and a height of 3 m, while a water tank shaped like a rectangular prism has a len

gth of 7 m, a width of 2 meters and a height of 2 meters. Which of the two tanks can hold more water? By how many cubic meters​
Mathematics
1 answer:
katrin2010 [14]2 years ago
7 0
The 1st one can vary more by 12 cubic meters
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Pls help this is due soon If the discriminate of a quadratic equation is negative___.
Makovka662 [10]

Answer:

<em>e. none of these</em>

Step-by-step explanation:

The correct answer is<em> e. none of these</em> because a negative discriminant means that there will be no solutions at all!

6 0
3 years ago
If they are right triangles
Ahat [919]
You can use Pythagreos theorem to determine it!
Pythagreos theorem is a^2 + b^2 = c^2
1) 4^2 + 4^2 = 6^2
   16    +  16  = 36
         32       = 36 (So this is not a right-angled triangle )
2) 16^2 + 12^2 = 20^2
      256 + 144  = 400
       400          = 400 (Sp this is a right-ngled triangle)
     
5 0
3 years ago
Read 2 more answers
Select all of the angles that have the same measure as angle 2. assume the lines are parallel
Phoenix [80]
4, 5, and 7 are the answer
6 0
3 years ago
Read 2 more answers
the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room​
Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

C.S.A.=2h(l+b)

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

C.S.A.=\text{Perimeter of the base} \times h

Putting the given values, we get

C.S.A.=18\times 3

C.S.A.=54

Therefore, the area of 4 walls of the room is 54 sq. metres.

7 0
3 years ago
Maria placed a rain gauge in her yard to measure the amount of rain that fell during the
julsineya [31]
.5 that your answer, just .5 your welcome
5 0
3 years ago
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