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ale4655 [162]
2 years ago
8

True or False?

Mathematics
1 answer:
neonofarm [45]2 years ago
7 0
FALSE!\\The\ segments\ below\ couldn't\ form\ a\ triangle.\\\\a,b,c-lengths\ sides\ of\ a\ triangle,\ then:\\\\a+b > c\\a+c > b\\b+c > c\\\\Here:a=9;\ b=4;\ c=15\\\\a+b=9+4=13 < 15!!!!
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Line w is perpendicular to the line y = −x − 5 and passes through the point (−2, 4). What is the y-intercept of line w?
Aleksandr [31]

The slope of a line perpendicular to another is the negative reciprocal of the original.  The negative reciprocal of -1 is 1.  The equation will read:

y=x+b

To solve for the y-intercept (b), plug in the given values of x and y:

4=-2+b

<em>*Add 2 to both sides*</em>

D. 6


Hope this helps!!

7 0
3 years ago
In a science test, Jamie solved 42 correct and 18 incorrect answers. What is the percentage of correct question?
uysha [10]
It would have to be B
4 0
2 years ago
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Can someone explain this to me?
Deffense [45]

Answer:

200

Step-by-step explanation:

So its basically you multiply the length by the width which is 15 times 5 which is 75 then you multiply 75 times 4 which is 200 so the answer is 200.

6 0
2 years ago
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Simplify the following expression 5^2-4/5+2
oee [108]
If <span>(5^2-4) / (5+2) then
=(25 - 4 )/3
= 21/3
= 7

if 4/5 fraction then
</span><span>5^2-4/5+2
= 25 - 4/5 + 2
= 27 - 4/5
= 26 5/5 - 4/5
= 26 1/5
= 26.2</span>
6 0
2 years ago
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The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad &#10;C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}&#10;\\\\\\&#10;AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad &#10;D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}&#10;\\\\\\&#10;BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}&#10;\\\\\\&#10;BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]&#10;\\\\\\&#10;4[15]\implies 60

7 0
2 years ago
Read 2 more answers
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