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nika2105 [10]
3 years ago
9

Will mark the brainiest! What are the coordinates of the vertex of the graph of f(x)=−3|x−1|?

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

well, the cheap answer is

f(x) = -3| x - 1 |  is really just  f(x) = -3| x - 1 | + 0.

now, what value of "x" makes the absolute value expression to 0?

well, let's just set it to 0 and check,

x - 1 = 0

x = 1

so if "x" ever becomes 1, the | x - 1| will turn to 0, therefore, the vertex is at   

f(x) = -3| (1) - 1 | + 0  -------------->  ( 1, 0 )

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1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
3 years ago
Someone please help me fast !!
kvv77 [185]
The second answer is correct.
6 0
3 years ago
Read 2 more answers
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