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asambeis [7]
9 months ago
12

Write the standard form of the line that passes through the given points. (7, -3) and (4,-8)

Mathematics
1 answer:
Mama L [17]9 months ago
3 0

The line equation is given by

y=mx+b

where <em>m </em>is the slope and <em>b </em>is the interception with <em>Y-axis</em>

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PLZZZZZ HELP
kari74 [83]
Answer: B


a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side.



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7 0
2 years ago
PLEASE HELP!!!
krok68 [10]
A parabola, a graph of a quadratic function, cannot have a maximum vertex and a minimum vertex at the same time because of the shape of the graph.  A parabola is a u-shaped graph.  The vertex of the parabola is the point where the u changes direction; if it was increasing, it starts to decrease, and if it was decreasing, it starts to increase.  Since a parabola only changes direction once, there will either be a minimum or a maximum, not both.
7 0
2 years ago
At the beginning of a snowstorm, Grayson had 10 inches of snow on his lawn. The snow then began to fall at a constant rate of 0.
maxonik [38]

Answer:

  • Grayson had 10 inches of snow in his lawn
  • the snow falls at a constant rate of 0.5 inches per hour
  • no snow was melting
  • the snow has fallen for 3 hours  

Let y be the height of the snow in the lawn

Grayson had 10 inches at the beginning (at t=0) so y= 10

3 hours passed so y= 10 + 3*0.5 = 11.5 inches

Grayson had 11.5 inches after three hours

Assuming that the snow continued to fall for an unkhown time t

y = 0.5*t + 10

we had 10 at the beginning so we add 10 (+10)

the snow is growing by 0.5 inches in the single hour so we multiply by 0.5

t is the time and it can 4, 5, 6 ...... hours

Just like a function :

  • 0.5 is the slope
  • t is the variable
  • 10 is the y-intercept

3 0
2 years ago
What is the area of something that is 2 inches long and 5/6 inches wide
Free_Kalibri [48]
Area = Length x Width

The Length is 2 inches
The Width is 5/6 inches

2 * (5/6) = 10/6

simplify and you get....
5/3
5 0
2 years ago
8wsquared2<br><img src="https://tex.z-dn.net/?f=8w%20%7B2%20%7D%5E%7B2%7D%20%20-%2018w" id="TexFormula1" title="8w {2 }^{2} - 1
balandron [24]

{\text{Here, we have the algebraic expression}} \hfill \\ 8w \times {2^2} - 18w \hfill \\ {\text{For simplifying the expression, first we solve the exponent part,}} \hfill \\ {\text{and then the resultant will be multiply with the monomial }}18w \hfill \\ 8w \times {2^2} - 18w \hfill \\ = 8 \times w \times {2^2} - 18w \hfill \\= \left( {8 \times {2^2}} \right) \times w - 18w\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ {\because \,{\text{By associative law }}a \times \left( {b \times c} \right) = \left( {a \times b} \right) \times c} \right] \hfill \\   = \left( {8 \times 4} \right) \times w - 18w \hfill \\   = 32 \times w - 18w \hfill \\= 32w - 18w \hfill \\= 14w \hfill \\

4 0
3 years ago
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