Answer:
3.9 mi/h
Step-by-step explanation:
If the boy is rowing perpendicular to the current, the two vectors form a right triangle.
AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat
AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37
AC = sqrt(15.37) = 3.9 mi/h
The boat's speed over the ground is 3.9 mi/h.
<u>Given</u>:
Four lines are marked proportion, the length of TW can be determined by
<u>Value of a:</u>
Let us set the proportion for the given lines.
Thus, we have;
Thus, the value of a is 5.6
<u>Value of b:</u>
Let us set the proportion for the given lines.
Thus, we have;
Thus, the value of b is 5.
<u>Length of TW:</u>
The length of TW is given by
Thus, the length of TW is 13.6
