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Veronika [31]
3 years ago
7

-25 Points-

Mathematics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

(x+4)^2+(y+2)^2=5

or

(x-(-4))^2+(y-(-2))^2=5

Step-by-step explanation:

Format for an equation of a circle: (x-h)^2+(y-k)^2=r^2

Center: (1/2*(-6-2),1/2*(-3-1))=(-4,-2)

Radius: sqrt(20)/2 or sqrt(5)

So, it's

(x+4)^2+(y+2)^2=5

or

(x-(-4))^2+(y-(-2))^2=5

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Which values are within the range of the piecewise-defined function?
musickatia [10]

Answer:  y < 1

<u>Step-by-step explanation:</u>

\begin{array}{c|c||l}\underline{x; x-3}&\underline{y=-x-2}&\\-3&-(-3)-2=1&\text{approaching but not including 1}\\-2&-(-2)-2=0&\\-1&-(-1)-2=-1&\end{array}

The first function has the range of y < -4

The second function has the range of y = -3

The third function has the range of y < 1

The largest y-value is 1 and the smallest y-value is -∞, therefore the range (y-values) are from -∞ to 1 → y < 1

6 0
3 years ago
Read 2 more answers
PLEASE HELP
Sholpan [36]
1) We have that the equation is x^2=20y , hence y=x^2/20. The standard equation of such an equation is y=\frac{1}{4p} x^2. Hence, p=5 in this case. The focus is at (0,5) and the directrix is at y=-5 (a tip is that the directrix is always "opposite" the focus point of a parabola; if the directrix is at x=-7 for example, the focus is at (7,0)).
2) Similarly, we have that the equation is x=3y^2 \\  \frac{1}{4p} =3. Thus, p=1/12. In this case, the parabola opens along the x-axis and the focus is at (1/12, 0). Also, the directrix is at x=-1/12. Hence the correct answer is B.
3) We are given that the parabola has a p of 9. Also, the focus lies along the y-axis, hence the parabola is opening along the y-axis. Finally, the focus is on the positive half, so the parabola is opening upwards. The equation for this case is y=y=\frac{1}{4p} x^2= \frac{1}{36 } x^2.
4) Similarly as above. The directrix is superfluous, we only need the p-value. THe same comments about the parabola apply and if we substitute p=8 in the formula: y= \frac{1}{4p} x^2 we get y=\frac{1}{32} x^2.
5) This is somewhat different, even though we do not need the directrix again. The focus lies on the x-axis, thus the parabola opens in this direction. The focus lies on the positive part of the axis, thus the parabola opens to the right. We also are given p=7. Hence, the equation we need is of the formx= \frac{1}{4p} y^2. Substituting p=7, we get x= \frac{1}{28} y^2.
6) The equation of a prabola with a vertex at (0,0) is of the form y=-ax^2. The minus sign is needed since the parabola is downwards. Since we are given anothe point, we can calculate a. We have to take y=-74 and x=14 feet (since left to right is 28, we need to take half). -a= \frac{y}{x^2} = \frac{-74}{14^2} =-0.378. Thus a=0.378. Hence the correct expressions is y=-0.378*x^2
7 0
3 years ago
Read 2 more answers
Hi, I am new to this website :) I'm currently taking an online trig class on De Moivre's theorem and I don't understand it at al
Vladimir [108]
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.

For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes

[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))] 

it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.

For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)

[2^6(cos(40*6))+isin(40*6)],

[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)

And the answer is -32 -32 √3 i

Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i

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3 years ago
What is There are fourteen whole snack bars on a plate. There are five friends.
AleksandrR [38]

Carl is incorrect. Dave ate a higher fraction of snack bars, by 0.2 snack bars.

Carl had .5 left of a snack bar.

Dave had .3 left of a snack bar.

Tony had .5 left of a snack bar.

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Tryone had .7 left of a snack bar.

If we add the above snack bars, there is a total of two remaining snack bars, meaning they only ate 12 of 14 snack bars.

3 0
3 years ago
What is the value of <img src="https://tex.z-dn.net/?f=%20a_%7B1%7D%20" id="TexFormula1" title=" a_{1} " alt=" a_{1} " align="ab
julia-pushkina [17]
The correct awnser is a or c i hope i helped
8 0
3 years ago
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