Find the eccentricity of the ellipse 4x^2 +16y^2 +32x-32y+16=0

1 answer:

7 0

4x² + 16y² + 32x - 32y + 16 = 0
 - 16 - 16
 4x² + 16y² + 32x - 32y = -16
 4x² + 32x + 16y² - 32y = -16
4(x² + 8x + 16) + 16(y² - 2y + 1) = -16 + 4(16) + 16(1)
 4(x + 4)² + 16(y - 1)² = -16 + 64 + 16
 4(x + 4)² + 16(y - 1)² = 48 + 16
 4(x + 4)² + 16(y - 1)² = 64
 64 64 64
 (x + 4)² + (y - 1)² = 1
 16 2

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Step-by-step explanation:

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