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3 years ago

Find the eccentricity of the ellipse 4x^2 +16y^2 +32x-32y+16=0

1 answer:

7 0

       4x² + 16y² + 32x - 32y + 16 = 0
<u>     - 16 - 16</u>
           4x² + 16y² + 32x - 32y = -16
           4x² + 32x + 16y² - 32y = -16
4(x² + 8x + 16) + 16(y² - 2y + 1) = -16 + 4(16) + 16(1)
      4(x + 4)² + 16(y - 1)² = -16 + 64 + 16
      4(x + 4)² + 16(y - 1)² = 48 + 16
      <u>4(x + 4)²</u> + <u>16(y - 1)²</u> = <u>64</u>
        64     64     64
      <u>(x + 4)²</u> + <u>(y - 1)²</u> = 1
   16 2

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lesantik [10]

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Explanation:

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Answer:

(a)

<u>Sample space:</u>

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2.c)in the diagram below, 4 m and ORIST at R. 5 $ 0 If m_1 = 63, find m_2.

pickupchik [31]

Data:

l and m are parallel lines

QR and ST are perpendicular in R

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Alternate angles are congruent, have the same measure.

$\begin{gathered} m\angle1=m\angle3 \\ \\ m\angle3=63 \end{gathered}$

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Use the equation above to find the measure of angle 2:

$\begin{gathered} \text{Subtract 153 in both sides of the equation:} \\ m\angle2+153-153=180-153 \\ \\ m\angle2=27 \end{gathered}$ Then, the measure of angle 2 is 27°

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