2 years ago

Find the eccentricity of the ellipse 4x^2 +16y^2 +32x-32y+16=0

1 answer:

7 0

4x² + 16y² + 32x - 32y + 16 = 0
 - 16 - 16
 4x² + 16y² + 32x - 32y = -16
 4x² + 32x + 16y² - 32y = -16
4(x² + 8x + 16) + 16(y² - 2y + 1) = -16 + 4(16) + 16(1)
 4(x + 4)² + 16(y - 1)² = -16 + 64 + 16
 4(x + 4)² + 16(y - 1)² = 48 + 16
 4(x + 4)² + 16(y - 1)² = 64
 64 64 64
 (x + 4)² + (y - 1)² = 1
 16 2

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Answer:

Step-by-step explanation:

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2 years ago

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Simplify the radical expression 5√7+2√175

yanalaym [24]

$5\sqrt{7} + 2\sqrt{175}=5\sqrt{7}+2\sqrt{25 \cdot 7}=5\sqrt{7}+ 2 \cdot \sqrt{25} \cdot \sqrt{7}= \\ \\ = 5\sqrt{7}+2 \cdot 5 \cdot \sqrt{7}=5\sqrt{7}+10\sqrt{7}=\boxed{15\sqrt{7}} \approx 39.69$

remember about formula $\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}$