Find the eccentricity of the ellipse
4x^2 +16y^2 +32x-32y+16=0
1 answer:
4x² + 16y² + 32x - 32y + 16 = 0
<u> - 16 - 16</u>
4x² + 16y² + 32x - 32y = -16
4x² + 32x + 16y² - 32y = -16
4(x² + 8x + 16) + 16(y² - 2y + 1) = -16 + 4(16) + 16(1)
4(x + 4)² + 16(y - 1)² = -16 + 64 + 16
4(x + 4)² + 16(y - 1)² = 48 + 16
<u>4(x + 4)²</u> + <u>16(y - 1)²</u> = <u>64</u>
64 64 64
<u>(x + 4)²</u> + <u>(y - 1)²</u> = 1
16 2
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