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3 years ago

How to solve 2/3(6x-9)=-34

1 answer:

5 0

$\frac{2}{3} (6x-9)=-34 \\ \\ \frac{2(6x - 9)}{3} =-34 \\ \\ \frac{2 \times 3(2x-3)}{3} =-34 \\ \\ \frac{6(2x - 3)}{3} = -34 \\ \\ 2(2x - 3) = -34 \\ \\ 2x - 3 - \frac{34}{2} \\ \\ 2x - 3 = -17 \\ \\ 2x -17 + 3 \\ \\ 2x = -14 \\ \\ x = - \frac{14}{2} \\ \\ x = -7 \\ \\ Answer: \fbox {x = -7}$

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Answer:81.31

Step-by-step explanation:

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3 years ago

Find the geometric mean of 2 and 3

Sav [38]

The first step in solving this problem is taking 2 and 3 and multiplying them (2 * 3 = 6) .
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3 years ago

The heights of women aged 20 to 29 follow approximately the N(64, 2.82) distribution. Men the same age have heights distributed

ivann1987 [24]

Answer:96.97

Step-by-step explanation:

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mean height of men $\mu _=69.3$

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4 0

3 years ago

Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti

almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

$d=v.t$

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

$d=(x+y).t_1$

Where t1=2.5 hours. Substituting values:

$20=(x+y)*2.5$

Rearranging, we find the downstream equation:

$2.5x+2.5y=20\qquad[1]$

The speed when rowing upstream is x-y, and the distance traveled is

$d=(x-y).t_2$

Where t2=5 hours. Substituting values:

$20=(x-y)*5$

Rearranging, we find the upstream equation:

$5x-5y=20\qquad[2]$

Multiplying [1] by 2:

$5x+5y=40$

Adding this equation to [2]:

$10x=60$

Solving:

$x=60/10=6$

Dividing [2] by 5:

$x-y=4$

Solving for y

$y=x-4=6-4=2$

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

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3 years ago

Lines g, h, and l are parallel and m< 2 = 132°.

xxMikexx [17]

M < 2 and m < 6 are corresponding angles and are equal....so < 6 = 132.

< 6 and < 8 form a line and are equal to 180

< 6 + < 8 = 180
132 + < 8 = 180
< 8 = 180 - 132
< 8 = 48 <===

4 0

3 years ago

Read 2 more answers