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mihalych1998 [28]
3 years ago
13

In Erewhon's money system, 12 mites equals 1 bit, and 20 bits equals 1 samolian. Johann has 3 samolians and 5 bits. How many mit

es is that?
Mathematics
1 answer:
Mila [183]3 years ago
8 0

3 samolians = 12 x 20 = 240 mites

5 bits = 60 mites

240 + 60 = 300

Final Answer:

300 mites

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To get the mean, you add up all of the values and then you divide by N, where N is the number of values in the list. In this case, you'll divide by N = 8.

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To find the median, you'll first sort the values from smallest to largest. You should have this set {65, 66, 68, 68, 70, 70, 72, 73} after sorting. Next, cross off the smallest and largest values to end up with this smaller set {66, 68, 68, 70, 70, 72}. We do this so we can locate the middle-most item.

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The midpoint of those two values is (68+70)/2 = 138/2 = 69. The median is 69. The mean and median may not always be the same value.

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The mode is the most frequent value. In this case, we have 68 and 70 show up exactly twice for each unique value. This is the most compared to the other unique values that only show up exactly once.

It is possible to have more than one mode, as long those values are more frequent than the rest. We denote the mode as a set, so the mode is {68, 70}

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