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2 years ago

1/3 cup of flour is used to make 5 dinner rolls.

2 answers:

5 0

So 1/3 cup is for 5 so
how much flower per dinner rol
1/3 divided by 5=(1/3)/5=1/3 times 1/5=1/15

1/15 cups used to make 1 dinner roll

with 5 and 2/3 cup
find how many 1/15 will fit
15/15=1 so 15 times 5=75
then 2/3 times 1 or 5/5=10/15 so
75+10=85 dinner rolls

Radda [10]2 years ago

3 0

Divide.

1/3 / 5

Or multiply by the reciprocal of 5:

1/3 * 1/5 = 1/15

Therefore 1/15 cup of flour is used to make 1 dinner roll.

We can set up a proportion:

5/1/3 = x/5 2/3

Multiply 5 2/3 to both sides:

28 1/3 / 1/3 = x

85 = x

So 85 rolls can be made with 5 2/3 cups of flour.

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The ratio of boys to girls on rowans swim team is 2:3.if there are 40 total swimmers on the team,how many of them are girls?

Bogdan [553]

Answer:

The ratio of girls is 24.

Step-by-step explanation:

If the total amount of swimmers is 40, you can divide it by 8 to get 5 multiples. If three of those 5's belong to the ratio of girls, the equation is 3 x 8. The answer is 24.

6 0

2 years ago

Ben made a model (shown below) of the square pyramid he plans to build when he grows up.

elena-s [515]

Answer:

$336 m^2$

Step-by-step explanation:

The surface area of a square pyramid is the sum of the area of the squared base + 4 times the area of each triangular face, therefore:

$A=A_b + 4A_t$

where:

$A_b=L^2$ is the area of the base, where

L is the length of the base

$A_t=\frac{1}{2}Lh$ is the area of each triangular face, where

h is the height of the face

Substituting,

$A=L^2+2Lh$

For the model in this problem,

L = 12

h = 8

Therefore, the surface area here is:

$A=12^2 +2(12)(8)=336$

4 0

2 years ago

Read 2 more answers

In a certain region, there is a 0.1 probability that any checked passerine bird's nest will

mamaluj [8]

Answer:

Probability of at least two cuckoo eggs is 0.738.

Step-by-step explanation:

probability of cuckoo egg = 0.1

probability of not a cuckoo egg = 1 - 0.1 = 0.9

Probability of at least two cuckoo eggs is

= Probability of two cuckoo eggs x probability of 1 not cuckoo egg +

probability of three cuckoo eggs

= 0.1 x 0.1 x 0.9 + 0.9 x 0.9 x 0.9

= 0.009 + 0.729

= 0.738

5 0

2 years ago

Given f(x)=3x+1, solve for x when f(x)=7

charle [14.2K]

Answer:

X = 22

Step-by-step explanation:

f(x) = 3x + 1

f(7) = 3(7) + 1

= 21 + 1

= 22

3 0

2 years ago

Read 2 more answers

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9

Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that $\mu = 8.9, \sigma = 2.9$

Sample of 37:

This means that $n = 37, s = \frac{2.9}{\sqrt{37}}$

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -0.53$

$Z = -0.53$ has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -3.08$

$Z = -3.08$ has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

7 0

2 years ago