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2 years ago

5

The perimeter of an isosceles triangle less than 20 inches. If the base is 5 inches, what is the maximum length of each of the l

egs?

1 answer:

ser-zykov [4K]2 years ago

4 0

Answer:

7.5 inches

Step-by-step explanation:

take the 5 away from the 20, you have 15 inches left. Isosceles triangles have two equal sides; 15 divided into two equally is 7.5

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In the figure lines 1, m, and n are parallel. A classmate says you can use the corollary to side-splitter theorem to find x. Exp

defon

Answer: You should not make that assumption in this problem.

The side-splitter theorem is about the line segments that are formed on the transverals themselves. It is not talking about the distances on the set of parallel lines. If you wanted to find the value of x, you should look for another way to prove the relationship involving the x-value.

6 0

2 years ago

Is 5_6 greater than less than or equal to 3/4

matrenka [14]

5/6=0.83~
Meanwhile 3/4=0.75.
5/6 is bigger than 3/4.
Good luck!

3 0

3 years ago

The graph shows the amount of a medicine min milligrams, remaining in a patient's body hours after receiving an injection . The

aksik [14]

An exponential function is a function defined by y = ab^x, where a represents the initial value, and b represents the rate

<h3>(a) The factor at which the medicine decreased, in 1.5 hour</h3>

From the graph, we have the following ordered pairs

(x,y) = (0,270) and (1.5,80)

Given that:

$y = ab^x$

At point (0,270), we have:

$ab^0=270$

$a= 270$

At point (1.5,80), we have:

$ab^{1.5} = 80$

Substitute 270 for a

$270b^{1.5} = 80$

Divide both sides by 270

$b^{1.5} = 0.2963$

Take 1.5th root of both sides

$b =0.44$

Hence, the medicine decrease in the hour and half at a factor of 0.44

<h3>(b) The factor at which the medicine decreased in the first half hour, and the first hour</h3>

In (a), we have:

The decay factor (b) to be 0.44

This represents the factor at which the medicine decreased throughout.

Hence, the medicine decrease in the first half hour, and the first hour at a factor of 0.44

<h3>(c) The exponential equation</h3>

In (a), we have:

$a= 270$

$b = 0.44$

So, the exponential equation is:

$y =270 * 0.44^x$

In terms of m and h, we have:

$m =270 * 0.44^h$

Hence, the equation relating m to h is $m =270 * 0.44^h$

Read more about exponential equations at:

brainly.com/question/11832081

6 0

2 years ago

Pls help will give brainliest!!!!!!!!!!!

finlep [7]

Answer:

ez

Step-by-step explanation:

6 0

2 years ago

Two samples are randomly selected from each population. The sample statistics are given below.

STALIN [3.7K]

Answer:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by:

$t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}$

And replacing we got:

$t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194$

And the best option would be:

2.19

Step-by-step explanation:

We have the following info given:

n1 = 150 n2 = 275

$\bar x_1 = 72.86, \bar x_2 = 67.34$

s1 = 15.98 s2 = 35.67

We want to test the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by:

$t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}$

And replacing we got:

$t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194$

And the best option would be:

2.19

7 0

2 years ago